For the answer to the question above asking <span>what is the probability that a randomly selected student will be a boy that brings his lunch to school? I'll provide a solution for the following problem below.
</span>P(boy |lunch) = P(boy and lunch)/P(lunch) = 0.40
P(boy and lunch) = P(lunch)*0.4 = 0.3*0.4 = 0.12
I think the answer is 15x^4y^5z^2
Your answer is going to be
23% :)
Pounds will be represented by x and the cost will be represented by y. The equation is Y=3x. For the graph just use substition for x and then calculate the outcome and graph it.
The answer would be 48 √6
