All categories

3 years ago

Explain how you use substitution to solve a system of linear equations.

2 answers:

7 0

The method of solving "by substitution" works by solving one of the equations (you choose which one) for one of the variables (you choose which one), and then plugging this back into the other equation, "substituting" for the chosen variable and solving for the other. Then you back-solve for the first variable.

lions [1.4K]3 years ago

7 0

Answer: Step 1 : First, solve one linear equation for y in terms of x .

Step 2 : Then substitute that expression for y in the other linear equation.

Step 3 : Solve this, and you have the x -coordinate of the intersection.

Step 4 : Then plug in x to either equation to find the corresponding y -coordinate.

Step-by-step explanation: MARK ME AS BRAINLIEST PLEASE PLEASE PLEASE!!!

You might be interested in

In a circle with a 8 in radius, how long, in inches, is an arc associated with 2.6 radians.

Bingel [31]

S = r·α is the formula to find the arc length (s), given the radius (r), and angle measure (α) in radians.
If the angle measure is NOT given in radians you must convert to radians.

s = 8 · 2.6
s = 20.8 in

7 0

3 years ago

Help asap pleaseeee (if u do ily)))

n200080 [17]

Answer:

B) 120

Step-by-step explanation:

180 - 60 = 120

Hope that helps!

4 0

3 years ago

Read 2 more answers

Which ordered pair is a solution to the system of linear equations One-half x minus three-fourths y = StartFraction 11 Over 60 E

s344n2d4d5 [400]

Answer:

$\left(\dfrac{2}{3},\dfrac{1}{5}\right)$

Step-by-step explanation:

Given the system of two equations:

$\left\{\begin{array}{l}\dfrac{1}{2}x-\dfrac{3}{4}y=\dfrac{11}{60}\\ \\\dfrac{2}{5}x+\dfrac{1}{6}y=\dfrac{3}{10}\end{array}\right.$

Multiply the first equation and the second equation by 60 to get rid of fractions:

$\left\{\begin{array}{l}30x-45y=11\\ \\24x+10y=18\end{array}\right.$

Now multiply the first equation by 4 and the second equation by 5:

$\left\{\begin{array}{l}120x-180y=44\\ \\120x+50y=90\end{array}\right.$

Subtract them:

$(120x-180y)-(120x+50y)=44-90\\ \\120x-180y-120x-50y=-46\\ \\-230y=-46\\ \\y=\dfrac{46}{230}=\dfrac{1}{5}$

Substitute it into the first equation:

$30x-45\cdot \dfrac{1}{5}=11\\ \\30x-9=11\\ \\30x=11+9\\ \\30x=20\\ \\x=\dfrac{2}{3}$

The solution is $\left(\dfrac{2}{3},\dfrac{1}{5}\right)$

4 0

3 years ago

Read 2 more answers

4(3m-8)=-80 solve each equation for the given variable

Bingel [31]

12m-32=-80
12m=-80+32
12m=-48
m=-4

8 0

3 years ago

Find the vertex of the graph of the function. f(x) = 2x^2 - 8x + 9

Rashid [163]

$\bf \textit{vertex of a vertical parabola, using coefficients} \\\\ f(x)=\stackrel{\stackrel{a}{\downarrow }}{2}x^2\stackrel{\stackrel{b}{\downarrow }}{-8}x\stackrel{\stackrel{c}{\downarrow }}{+9} \qquad \qquad \left(-\cfrac{ b}{2 a}~~~~ ,~~~~ c-\cfrac{ b^2}{4 a}\right) \\\\\\ \left(-\cfrac{-8}{2(2)}~~,~~9-\cfrac{(-8)^2}{4(2)} \right)\implies \left( \cfrac{8}{4}~~,~~9-\cfrac{64}{8} \right) \\\\\\ (2~~,~~9-8)\implies (2~~,~~1)$

5 0

3 years ago