Given:
4log1/2^w (2log1/2^u-3log1/2^v)
Req'd:
Single logarithm = ?
Sol'n:
First remove the parenthesis,
4 log 1/2 (w) + 2 log 1/2 (u) - 3 log 1/2 (v)
Simplify each term,
Simplify the 4 log 1/2 (w) by moving the constant 4 inside the logarithm;
Simplify the 2 log 1/2 (u) by moving the constant 2 inside the logarithm;
Simplify the -3 log 1/2 (v) by moving the constant -3 inside the logarithm:
log 1/2 (w^4) + 2 log 1/2 (u) - 3 log 1/2 (v)
log 1/2 (w^4) + log 1/2 (u^2) - log 1/2 (v^3)
We have to use the product property of logarithms which is log of b (x) + log of b (y) = log of b (xy):
Thus,
Log of 1/2 (w^4 u^2) - log of 1/2 (v^3)
then use the quotient property of logarithms which is log of b (x) - log of b (y) = log of b (x/y)
Therefore,
log of 1/2 (w^4 u^2 / v^3)
and for the final step and answer, reorder or rearrange w^4 and u^2:
log of 1/2 (u^2 w^4 / v^3)
Answer: The Nth power xN of a number x was originally defined as x multiplied by itself, until there is a total of N identical factors. By means of various generalizations, the definition can be extended for any value of N that is any real number.
(2) The logarithm (to base 10) of any number x is defined as the power N such that
x = 10N
(3) Properties of logarithms:
(a) The logarithm of a product P.Q is the sum of the logarithms of the factors
log (PQ) = log P + log Q
(b) The logarithm of a quotient P / Q is the difference of the logarithms of the factors
log (P / Q) = log P – log Q
(c) The logarithm of a number P raised to power Q is Q.logP
log[PQ] = Q.logP
Step-by-step explanation:
Answer:
Another way to identify the domain and range of functions is by using graphs. Because the domain refers to the set of possible input values, the domain of a graph consists of all the input values shown on the x-axis. The range is the set of possible output values, which are shown on the y-axis.
So i think it will be -1
Answer:
The net sales for last month were <u>$19,525</u>.
Step-by-step explanation:
Given:
Last month sales were $24,000.
Discounts is $3,500 and $975 in returns.
Now, to get the net sales for last month.
So, we deduct the discount:
<em>Sales - discounts</em> = 
Then, we deduct the returns from the remaining amount:
<em>Sales after discounts - returns</em> = 
= 
Therefore, the net sales for last month were $19,525.
