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Alla [95]
3 years ago
15

Please help ASAP !!!!!

Mathematics
2 answers:
sasho [114]3 years ago
3 0

Since the denominators (bottom of the fraction) are the same, we can subtract the numerators (the top parts) easily.

14/19 - 5/19 = 9/19

ANSWER: 9/19

Lana71 [14]3 years ago
3 0

14/19-5/19

Minus the numerators together

14-5=9

The denominators stay the stay

Answer: 9/19

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A pendant is formed using a cylinder and cone. Once assembled, as shown below, the pendant is painted. How many square millimete
solmaris [256]
Surface area of cylinder is given by area of circle + area of the rectangle that curved around the cylinder

Area of the base of the cylinder = \pi r^{2} = 8^{2} \pi =64 \pi
Area of the cylinder 'wall' = width × length = 12×2r \pi=12×16 \pi=192 \pi

Note that the wall of the cylinder is in the shape of a rectangle. The width of the rectangle is the height of the cylinder. The length of the rectangle is the circumference of the circle base.

Surface area of cone is given by \pirl where l is the slanted height of the cone

SA of cone = \pi (8)(10)=80 \pi

Hence total painted surface area is 80 \pi +192 \pi +64 \pi =336 \pi


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3 years ago
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What is the slope of the line​
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Given that f.x 3x-2 over x+1 g[x] x +5 evaluate f[-4] and gf [-2]
Jobisdone [24]

The value of f[ -4 ] and g°f[-2] are \frac{14}{3} and 13 respectively.

<h3>What is the value of f[-4] and g°f[-2]?</h3>

Given the function;

  • f(x) = \frac{3x-2}{x+1}
  • g(x)=x+5
  • f[ -4 ] = ?
  • g°f[ -2 ] = ?

For f[ -4 ], we substitute -4 for every variable x in the function.

f(x) = \frac{3x-2}{x+1}\\\\f(-4) = \frac{3(-4)-2}{(-4)+1}\\\\f(-4) = \frac{-12-2}{-4+1}\\\\f(-4) = \frac{-14}{-3}\\\\f(-4) = \frac{14}{3}

For g°f[-2]

g°f[-2] is expressed as g(f(-2))

g(\frac{3x-2}{x+1}) =  (\frac{3x-2}{x+1}) + 5\\\\g(\frac{3x-2}{x+1}) =  \frac{3x-2}{x+1} + \frac{5(x+1)}{x+1}\\\\g(\frac{3x-2}{x+1}) =  \frac{3x-2+5(x+1)}{x+1}\\\\g(\frac{3x-2}{x+1}) =  \frac{8x+3}{x+1}\\\\We\ substitute \ in \ [-2] \\\\g(\frac{3x-2}{x+1}) =  \frac{8(-2)+3}{(-2)+1}\\\\g(\frac{3x-2}{x+1}) =  \frac{-16+3}{-2+1}\\\\g(\frac{3x-2}{x+1}) =  \frac{-13}{-1}\\\\g(\frac{3x-2}{x+1}) =  13

Therefore, the value of f[ -4 ] and g°f[-2] are \frac{14}{3} and 13 respectively.

Learn more about composite functions here: brainly.com/question/20379727

#SPJ1

6 0
2 years ago
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