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Maru [420]
3 years ago
15

If the first term of AP is 4 and the sum of first five term is equal to one-fourth of the sum of the next five term, then find t

he 15th term?​
Mathematics
1 answer:
patriot [66]3 years ago
5 0

Answer:

15th term = 116

Step-by-step explanation:

a= 4

Sum of an A.P = n/2 {2a + (n-1)d}

sum of first five term is equal to one-fourth of the sum of the next five term

5/2{ 2*4 + (5-1)d} = 1/4 × 10/2{2*4 + (10-1)d

5/2 {8 + 4d} = 1/4 × 5{ 8 + 9d}

40/2 + 20/2d = 1/4{ 40 + 45d)

20 + 10d= 40/4 + 45/4d

20 + 10d = 10 + 45/4d

20 - 10 = 45/4d - 10d

10 =45d - 40d /4

10 = 5/4d

Divide both sides by 5/4

10 ÷5/4 = d

10×4/5 = d

40/5 = d

8 = d

d= 8

Find the 15th term

15th term = a + (n-1)d

= 4 + (15-1)8

= 4 + (14)8

= 4 + 112

= 116

The 15th term is 116

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Answer:

  B = 2M -A

Step-by-step explanation:

For given endpoint A and midpoint M, the other endpoint B can be found using the definition of the midpoint:

  M = (A+B)/2

  2M = A+B . . . . . multiply by 2

  2M-A = B . . . . . subtract A

The second endpoint can be found by subtracting the given endpoint from twice the midpoint:

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3 years ago
What is the measurement of the longest line segment in a right rectangular prism that is 26 inches long, 2 inches wide, and 2 in
EastWind [94]

Answer:

6\sqrt{19} \approx 26.153 inches.

Step-by-step explanation:

The longest line segment in a right rectangular prism is the diagonal that connects two opposite vertices. On the first diagram attached, the green line segment connecting A and G is one such diagonals. The goal is to find the length of segment \mathsf{AG}.

In this diagram (not to scale,) \mathsf{AB} = 26 (length of prism,) \mathsf{AC} = 2 (width of prism,) \mathsf{AE} = 2 (height of prism.)

Pythagorean Theorem can help find the length of \mathsf{AG}, one of the longest line segments in this prism. However, note that this theorem is intended for right triangles in 2D, not the diagonal in a 3D prism. The workaround is to simply apply this theorem on two different right triangles.

Start by finding the length of line segment \mathsf{AD}. That's the black dotted line in the diagram. In right triangle \triangle\mathsf{ABD} (second diagram,)

  • Segment \mathsf{AD} is the hypotenuse.
  • One of the legs of \triangle\mathsf{ABD} is \mathsf{AB}. The length of \mathsf{AB} is 26, same as the length of this prism.
  • Segment \mathsf{BD} is the other leg of this triangle. The length of \mathsf{BD} is 2, same as the width of this prism.

Apply the Pythagorean Theorem to right triangle \triangle\mathsf{ABD} to find the length of \mathsf{AB}, the hypotenuse of this triangle:

\mathsf{AD} = \sqrt{\mathsf{AB}^2 + \mathsf{BD}^2} = \sqrt{26^2 + 2^2}.

Consider right triangle \triangle \mathsf{ADG} (third diagram.) In this triangle,

  • Segment \mathsf{AG} is the hypotenuse, while
  • \mathsf{AD} and \mathsf{DG} are the two legs.

\mathsf{AD} = \sqrt{26^2 + 2^2}. The length of segment \mathsf{DG} is the same as the height of the rectangular prism, 2 (inches.) Apply the Pythagorean Theorem to right triangle \triangle \mathsf{ADG} to find the length of the hypotenuse \mathsf{AG}:

\begin{aligned}\mathsf{AG} &= \sqrt{\mathsf{AD}^2 + \mathsf{GD}^2} \\ &= \sqrt{\left(\sqrt{26^2 + 2^2}\right)^2 + 2^2}\\ &= \sqrt{\left(26^2 + 2^2\right) + 2^2} \\&= 6\sqrt{19} \\&\approx 26.153\end{aligned}.

Hence, the length of the longest line segment in this prism is 6\sqrt{19} \approx 26.153 inches.

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