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ch4aika [34]
3 years ago
6

Tommy has a pet monkey. Every day, his monkey eats 4 apples in the morning. The monkey also eats two bananas for every banana to

m eats
Mathematics
1 answer:
Kipish [7]3 years ago
8 0
So, if tom eats 10 bananas in 10 days

than, monkey have eaten 40 apples and 20 bananas 

hope this helped

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please help i’m not tryna fail algebra i can’t figure this out(solve by substitution and show steps please)
Brut [27]

Answer:

y=8-6x

Step-by-step explanation:

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3 years ago
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What are the domain, range, and asymptote of h(x) = (1.4)^x + 5?
Elena L [17]

Answer:

A.Domain:{x\x is a real number }

Range:{y\y>5}

Asymptote :y=5

Step-by-step explanation:

We are given that a function

h(x)=(1.4)^x+5

We have to find the domain, range and asymptote of h(x).

It is exponential function therefore, it is defined for all values of x.

Hence, domain  of h(x)={x| x is a real number}

Substitute x=0 then we get

h(0)=(1.4)^0+5=1+5=6

(a^0=1)

Hence, range of h(x)={y|y>5}

For exponential function,

Horizontal asymptote:a^x\rightarrow 0 when x\rightarrow-\infty

Apply limit x\rightarrow-\infty

\lim_{x\rightarrow-\infty}h(x)=\lim_{x\rightarrow-\infty}(1.4)^x+5=0+5=5

e^{-\infty}=0

\lim_{x\rightarrow \infty}(1.4)^x+5=\infty

Hence, the horizontal asymptote y=5.

6 0
3 years ago
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Set up an equation and solve the following problem.
nordsb [41]

Answer:

The speed of Dave is 42 miles per hour

The speed of Kent is 46 miles per hour .

Step-by-step explanation:

Given as :

The distance cover by Dave = d = 210 miles

The time taken by Dave = t hour

The speed of Dave = s miph

<u>Again</u>

The distance cover by Kent = D = 230 miles

The time taken by Kent = T hour

The speed of Kent = S = (s + 4 ) miph

<u>For Dave</u>

Time = \dfrac{\textrm Distance}{\textrm Speed}

So, t = \dfrac{\textrm d miles}{\textrm s miph}

Or, t = \dfrac{\textrm 210 miles}{\textrm s miph}

<u>For Kent</u>

Time = \dfrac{\textrm Distance}{\textrm Speed}

So, T = \dfrac{\textrm D miles}{\textrm S miph}

Or, T = \dfrac{\textrm 230 miles}{\textrm (s + 4) miph}

∵ Time taken by both is same

So, t = T

Or,  \dfrac{\textrm 210 miles}{\textrm s miph} = \dfrac{\textrm 230 miles}{\textrm (s + 4) miph}

Or, 210 × (s + 4) = 230 × s

Or, 210 × s + 210 × 4 = 230 × s

Or, 210 × 4 = 230 × s -210 × s

Or, 210 × 4 = 20 × s

∴  s = \dfrac{840}{20}

i.e s = 42 miph

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Again

The speed of Kent = S = (s + 4 ) miph

i.e S = 42 + 4

or, S = 46 miph

So, The speed of Kent = S = 46 miles per hour

Hence,The speed of Dave is 42 miles per hour

And The speed of Kent is 46 miles per hour . Answer

8 0
3 years ago
What is 600 is 10 times as much as
svetoff [14.1K]

Let x = our unknown number

10x = 600

Divide by 10 on both sides to isolate the variable x.

x = 600/10

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600 is 10 times as much as 60.

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4 years ago
(9,-9), (13,-3) djfjfifugjfjjdjd​
kondaur [170]

Answer:

it would be in 2nd quadrant

Step-by-step explanation:

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