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ch4aika [34]
3 years ago
6

Tommy has a pet monkey. Every day, his monkey eats 4 apples in the morning. The monkey also eats two bananas for every banana to

m eats
Mathematics
1 answer:
Kipish [7]3 years ago
8 0
So, if tom eats 10 bananas in 10 days

than, monkey have eaten 40 apples and 20 bananas 

hope this helped

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What is 5 over 4 in math
bixtya [17]

Answer:

An improper fraction

Step-by-step explanation:

In improper fraction is when the numerator (top number) is greater than or equal to the denominator (bottom number)

3 0
2 years ago
Let f be defined by the function f(x) = 1/(x^2+9)
riadik2000 [5.3K]

(a)

\displaystyle\int_3^\infty \frac{\mathrm dx}{x^2+9}=\lim_{b\to\infty}\int_{x=3}^{x=b}\frac{\mathrm dx}{x^2+9}

Substitute <em>x</em> = 3 tan(<em>t</em> ) and d<em>x</em> = 3 sec²(<em>t </em>) d<em>t</em> :

\displaystyle\lim_{b\to\infty}\int_{t=\arctan(1)}^{t=\arctan\left(\frac b3\right)}\frac{3\sec^2(t)}{(3\tan(t))^2+9}\,\mathrm dt=\frac13\lim_{b\to\infty}\int_{t=\arctan(1)}^{t=\arctan\left(\frac b3\right)}\mathrm dt

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(b) The series

\displaystyle \sum_{n=3}^\infty \frac1{n^2+9}

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\displaystyle\sum_{n=3}^\infty\frac1{n^2}

(c) The series

\displaystyle \sum_{n=1}^\infty \frac{(-1)^n (n^2+9)}{e^n}

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\displaystyle \sum_{n=1}^\infty \left|\frac{(-1)^n (n^2+9)}{e^n}\right|=\sum_{n=1}^\infty \frac{n^2+9}{e^n} < \sum_{n=1}^\infty \frac{n^2}{e^n} < \sum_{n=1}^\infty \frac1{e^n}=\frac1{e-1}

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2 years ago
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Tanzania [10]

I guess you mean that the zeroes are 2 and -3/5.

In factor form the function  could be

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Answer:

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