Answer: below
Step-by-step explanation: Given f(x) =kxn where k is a constant, then f'(x) = nkx(n - 1)
Can you apply this principle to this problem, Let me know if you have any further questions about this problem. Thanks.
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Let A = the event that the first ball is odd number
and B = the event that the second ball is odd number
In the beginning, there are 25 balls which contain 13 balls of odd numbers. So the probability for the first selection (as to expect you would draw a ball of an odd number) is
P(A) = 13/25
After the selection, the rule does not allow replacement. So, there are 24 balls left containing now 12 balls of odd numbers. So the probability for the second selection (as to expect you would draw also a ball of odd number) is
P(B) = 12/24 = 1/2
Multiplying the two probabilities obtains
P(2 odd numbers) = 13/25 * 1/2 = 13/50
Answer:
5 cats, 1 fish and 94 birds
Step-by-step explanation:
Let
- c be the number of cats;
- b be the number of birds;
- f be the number of fish.
A kid bought 100 toy animals, then
If a cat costs $10.00, then c cats cost $10c.
If a fish costs $3.00, then f fish cost $3f.
If a bird costs $0.50, then b birds cost $0.5b.
In total,
We get the system of two equations:
From the first equation:
Substitute it into the second equation:
Number f must be a whole number greater than 0, so
Number c must be a multiple of 5, thus the only possible value for c is 5.
When c = 5, then
Answer:
Start by moving the decimal place in the number until you have a coefficient between 1 and 10. The number of places to the left that you had to move the decimal point is the exponent. so for example, 0.000345 would be 3.45(10)^4
Step-by-step explanation:
Hope that helps!
-3(2)-3(2)3+-3(2)+2(2)3--3(2)
I got -12
