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Allisa [31]
4 years ago
14

Malorie can work 10 math problems in 3 minutes. At this rate, how many problems can she work in one hour?

Mathematics
1 answer:
lisov135 [29]4 years ago
4 0
D
If you multiply 3 by 10 and add a zero onto the ten in the question that is 100 in half an hour, all you need to do then is multiply that answer by two to get your answer.
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For f(x) = 3x2 - 2, find F(x) =<br> f(x)dx
klemol [59]

Answer: below

Step-by-step explanation: Given f(x) =kxn where k is a constant, then f'(x) = nkx(n - 1)

Can you apply this principle to this problem, Let me know if you have any further questions about this problem. Thanks.

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7 0
4 years ago
Read 2 more answers
A bowl contains 25 balls numbered 1 to 25. A ball is drawn and its number is noted. Without replacing the first ball, another ba
mamaluj [8]
Let A = the event that the first ball is odd number
and B = the event that the second ball is odd number

In the beginning, there are 25 balls which contain 13 balls of odd numbers. So the probability for the first selection (as to expect you would draw a ball of an odd number) is
P(A) = 13/25

After the selection, the rule does not allow replacement. So, there are 24 balls left containing now 12 balls of odd numbers. So the probability for the second selection (as to expect you would draw also a ball of odd number) is
P(B) = 12/24 = 1/2

Multiplying the two probabilities obtains
P(2 odd numbers) = 13/25 * 1/2 = 13/50

6 0
4 years ago
A kid spent $100.00 to get 100 toy animals. The child bought at least one cat, one fish, and one bird, and did not buy any other
Rama09 [41]

Answer:

5 cats, 1 fish and 94 birds

Step-by-step explanation:

Let

  • c be the number of cats;
  • b be the number of birds;
  • f be the number of fish.

A kid bought 100 toy animals, then

c+b+f=100

If a cat costs $10.00, then c cats cost $10c.

If a fish costs $3.00, then f fish cost $3f.

If a bird costs $0.50, then b birds cost $0.5b.

In total,

10c+3f+0.5b=100

We get the system of two equations:

\left\{\begin{array}{l}c+b+f=100\\10c+3f+0.5b=100\end{array}\right.

From the first equation:

b=100-c-f

Substitute it into the second equation:

10c+3f+0.5(100-c-f)=100\\ \\10c+3f+50-0.5c-0.5f=100\\ \\9.5c+2.5f=50\\ \\95c+25f=500\\ \\19c+5f=100\\ \\f=20-\dfrac{19}{5}c

Number f must be a whole number greater than 0, so

20-\dfrac{19}{5}c>0\\ \\c

Number c must be a multiple of 5, thus the only possible value for c is 5.

When c = 5, then

f=20-5\cdot \dfrac{19}{5}=20-19=1\\ \\b=100-5-1=94

8 0
4 years ago
Explain how to convert numbers from standard form to scientific.
sweet [91]

Answer:

Start by moving the decimal place in the number until you have a coefficient between 1 and 10. The number of places to the left that you had to move the decimal point is the exponent. so for example, 0.000345 would be 3.45(10)^4

Step-by-step explanation:

Hope that helps!

8 0
3 years ago
Find −a2 − 3b3 + c2 + 2b3 − c2 if a = 3, b = 2, and c = −3.
Elodia [21]
-3(2)-3(2)3+-3(2)+2(2)3--3(2)
I got -12
5 0
4 years ago
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