6)
KM bisects on <NKL so m<MKN = m<MKL = 3x + 5
2(m<MKL) + m<JKN = 180
2(3x+5) + 8x + 2 = 180
6x + 10 + 8x + 2 = 180
14x + 12 = 180
14x = 168
x = 12
so
m<MKN = m<MKL = 3x + 5 = 3(12) + 5 = 36 + 5 = 41
answer
b. 41
7)
2 supplementary has sum = 180
x + x + 14 = 180
2x + 14 = 180
2x = 166
x = 83
x + 14 = 83 + 14 = 97
2 angles are 83 and 97
answer
b. 83, 97
Let the integers be x-2, x, x+2.
Given,
x -2 + x + x + 2 = 69
3x = 69
x = 23
Hence, the integers are 21, 23 and 25.
Answer:
(-5, 8)
Step-by-step explanation:
Step 1: Multiply 2nd equation by -1
x + y = 3
-y = -8
Step 2: Elimination
x = -5
Step 3: Find <em>y</em>
y = 8
81 + 70 + x = 3(73)
first multiply 3(73)
81 + 70 + x = 219
combine like terms
151 + x = 219
subtract 151 from both sides
x = 68
Joaquin needs to score a 68 on her next test to maintain an average of 73.
