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Grace [21]
4 years ago
13

Anthony wants to make two different rectangular flowerbeds ,each with an area of 24 square feet .he will build a wooden frame ar

ound each flower bed.the flowerbeds will have side lengths that are whole numbers.
Mathematics
2 answers:
Alina [70]4 years ago
4 0
Anthony wants to make two different
rectangular flowerbeds, each with an area of 24 square
feet. He will build a wooden frame around each
flowerbed. The flowerbeds will have side lengths that are
whole numbers.
Part A
Each unit square on the grid below is 1 square foot. Draw
two possible flowerbeds. Label each with a letter.


Part B
Which of the flowerbeds will take more wood to frame?
Explain how you know.
nignag [31]4 years ago
3 0
One of them is 3,8,3,8 and the other is 4,6,4,6
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10 Type the correct answer in the box. Use numbers instead of words. Use a calculator to help solve the problem. а A community g
MatroZZZ [7]

Answer:

$130.68

Step-by-step explanation:

1 acre = 43,560 square feet

3/4 of 43560 = 32,670 (So that would be 76,230 sq ft in 1.75 acres because 43560 + 32670 = 76230)

We need to divide the total by 35 plots.

76230 / 35 = 2178, using long division.

2,178 square feet is just one plot of 35. We need to multiply 2178 by 0.06.

Answer: $130.68

pls mark brainliest need 5 more for genius rank!

6 0
3 years ago
Please help with this question
vovikov84 [41]

Answer:

384π cm³

Step-by-step explanation:

Formula for the volume of a cone is \displaystyle \large{\frac{1}{3}\pi r^2 h} where:—

  • r is radius
  • h is height

Our radius is given in an attachment which is 12 cm and height is 8 cm. Substitute these values in the formula:—

\displaystyle \large{V = \frac{1}{3}\pi (12)^2 \cdot 8}\\\displaystyle \large{V = \frac{1}{3}\pi \cdot 144 \cdot 8}\\\displaystyle \large{V = 48 \pi \cdot 8}\\\displaystyle \large{V = 384 \pi}

__________________________________________________________

<u>Summary</u>

  <u>Volume (Cone)</u>

\displaystyle \large{V = \frac{1}{3}\pi r^2 h} where:—

h is height or perpendicular.

r is radius.

  <u>Value of Pi (Commonly Used)</u>

\displaystyle \large{\pi \approx 3.14}

__________________________________________________________

If you have any questions regarding this problem or need clarification for my answer or explanation, do not hesitate to ask in comment! Good luck on your assignment and have a great day!

7 0
2 years ago
There are 348 identical plastic chips numbered 1 through 348 in a box. What is the probability of reaching into the box and rand
hoa [83]
<h2>P(E) = \dfrac{53}{87} or, 0.6092</h2>

Step-by-step explanation:

Given,

There are 348 identical plastic chips numbered 1 through 348 in a box.

To find, the probability of reaching into the box and randomly drawing a chip number which is smaller than 213 = ?

Total number of possible outcomes = 348

Let E be the event of getting randomly drawing a chip number that is smaller than 213.

Favourable outcomes are:

1, 2, 3, .............., 212

Number of favourable outcomes = 212

∴ Probability =

P(E) =

= \dfrac{53}{87} or, 0.6092

Thus, P(E) = \dfrac{53}{87} or, 0.6092

4 0
4 years ago
Animals: The label on a bottle of pet vitamins lists dosage guidelines. What dosage would you give to each of these animals? (a)
Salsk061 [2.6K]

Answer:

a) 1 tsp.

b) 1.5 tsp.

c) 2 tsp.

Step-by-step explanation:

Complete Correct Question

Animals: The label on a bottle of pet vitamins lists dosage guidelines. What dosage would you give to each of these animals? (a) a 18 kg adult dog (b) a 6 kg cat (c) 18 kg pregnant dog

- The dosage listed for adult dog is 1/2 tsp per 9 kg dog weight.

- The dosage listed for adult cat is 1/4 tsp per 1 kg weight.

- The dosage listed for pregnant dog is 1/2 tsp per 4.5 kg dog weight.

Solution

a) 18 kg adult dog

The dosage listed for adult dog is 1/2 tsp per 9 kg dog weight.

9 kg dog weight = (1/2) tsp

18 kg adult dog = (18/9) × (1/2) = 1 teaspoon.

b) 6 kg cat

The dosage listed for adult cat is 1/4 tsp per 1 kg weight.

1 kg cat = (1/4) tsp

6 kg cat = (6/1) × (1/4) = (6/4) = 1.5 teaspoons.

c) 18 kg pregnant dog

The dosage listed for pregnant dog is 1/2 tsp per 4.5 kg dog weight.

4.5 kg dog weight = (1/2) tsp

18 kg pregnant dog = (18/4.5) × (1/2) = 2 teaspoons.

Hope this Helps!!!

4 0
4 years ago
Read 2 more answers
Factor 18x 6y using the greatest common factor
elena55 [62]
18x and 6y, though i can't see the operation between, can be factored by dividing out a 6. 6 is the greatest common factor, as it's a multiple of 18.

for 18x + 6y: 6(3x + y) is the factored form. if your symbol is subtraction, it's basically the same, you just change the sign.
6 0
4 years ago
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