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Lady_Fox [76]
3 years ago
6

Which set of ordered pairs represents a function?

Mathematics
1 answer:
PSYCHO15rus [73]3 years ago
7 0
Your answer would be C im pretty sure
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Tamara has 12 pencils. There are three red pencils and p other pencils. Write an equation to represent this situation.
Novosadov [1.4K]
The answer is either 3+x=12 or 3x=12
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Can someone help me with this please?
Simora [160]
The answer would be C
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use the explicit formula an = a1 + (n - 1) * d to find the 500th term of the sequence below. 24,30,36,42,48,... A. 3018 B. 3042
marishachu [46]

Answer:

Option A.

Step-by-step explanation:

The given sequence is  

24, 30, 36, 42, 48, ...

It is an AP. Here,  

First term = 24

Common difference = 30-24 = 6

The given explicit formula for nth term is

a_n=a_1+(n-1)d

where, a_1 is first term, d is common difference.

Substitute a_1=24, d=6 \text{ and }n=500 in the above formula.

a_{500}=24+(500-1)(6)

a_{500}=24+(499)(6)

a_{500}=24+2994

a_{500}=3018

The 500th term of the sequence is 3018.

Therefore, the correct option is A.

3 0
3 years ago
Sec s = 1.6948
Anastaziya [24]
That'd be true only if the value of "s" is the exact same one for both
namely  if sec(s) = cos(s)
then solving for "s"
thus

\bf sec(s)=cos(s)\qquad but\implies sec(\theta)=\cfrac{1}{cos(\theta)}
\\\\\\
thus\cfrac{1}{cos(s)}=cos(s)\implies 1=cos^2(s)\implies \pm \sqrt{1}=cos(s)
\\\\\\
\pm 1=cos(s)\impliedby \textit{now taking }cos^{-1}\textit{ to both sides}
\\\\\\
cos^{-1}(\pm 1)=cos^{-1}[cos(s)]\implies cos^{-1}(\pm 1)=\measuredangle s
5 0
3 years ago
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