Answer:
x = - 1
Step-by-step explanation:
Given
4x = x^2 - 5 Transfer 4x to the right side.
Solution
x^2 - 4x - 5 = 0 Factor
(x - 5)(x + 1)
You want the negative solution. That means that the middle sign must be plus.
x + 1 = 0 Subtract 10 from both sides
x = - 1 Ten on the left disappears by the subtraction process.
Is that correct?
4x = x^2 - 5
x = - 10
4*(-1) = (-1)^2 - 5
-4 = ? 1 - 5
-4 = - 4
and it does work.
Given that the triangle is a right angled triangle, to solve for x we shall use the Pythagorean theorem given by:
c^2=a^2+b^2
where:
c is the hypotenuse
a and b are the legs.
c=10
a=6
b=(x-6)
thus plugging the values in the equation and solving for x we get:
10^2=6^2+(x-6)^2
100=36+x^2-12x+36
100=x^2-12x+72
0=x^2-12x-28
factoring the above we get:
0=(x+2)(x-14)
hence
x=-2 or x=14
given that there is no negative distance then
x=14
thus the value of x is 14
You can substitute what y is into the second equation, so:
3x + 4(2x + 1) = 26
3x + 8x + 4 = 26
11x + 4 = 26
- 4
11x = 22
÷ 11
x = 2
y = (2 × 2) + 1
y = 5 + 1
y = 5
So you get x as 2 and y as 5, I hope this helps!
20+(-3.05)+(-9.8)=20-3.05-9.8=7.15