Let the 1st number be x; 2nd number be y; 3rd number be z.
x + y + z = 79
x = number we are looking for.
y = x * 5 ==> 5 times the first
z = x + 16 ==> 16 more than the first
Therefor,
x + (x * 5) + (x+16) = 79
1st step, multiply the 2nd number: x * 5 = 5x
x + 5x + x + 16 = 79
Add all like numbers:
7x + 16 = 79
To get x, transfer 16 to the other side and change its sign from positive to negative.
7x = 79 - 16
7x = 63
To get x, divide both sides by 7
7x/7 = 63/7
x = 9
To check. Substitute x by 9.
x + (x * 5) + (x+16) = 79
9 + (9 * 5) + (9 + 16) = 79
9 + 45 + 25 = 79
79 = 79 equal. value of x is correct.
Answer:
∠ D = 28°
Step-by-step explanation:
The external angle of a triangle is equal to the sum of the 2 opposite interior angles.
∠ EBC is an exterior angle of Δ ABE, thus
∠ EBC = 90° + 34° = 124°
BD bisects ∠ EBC, so
∠ EBD = 124° ÷ 2 = 62° , then
∠ D = 180° - (90 + 62)° = 180° - 152° = 28° ( angle sum of triangle )
Answer:
she gets her drivers license then right?
Step-by-step explanation:
The answer is C, 1.
In a number line, the larger number it gets, the more of the right side they're. The smaller the number, the more left side they get.
So, on a number line, 1 is just at the right side of 0, all the other options are at least one more place away from 0.
