A 7.36 g sample of copper is contaminated with a additional 0.51 g sample of zinc. suppose an atomic mass measurement was perfor
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Answer:
The concentration of the acid is 117.92 ± 0.03 mM.
Explanation:
In this problem, the concentration of NaOH and the volume used is given. The volume pipetted from the acid is also given. The concentration of the acid is given by:
CNaOH * VNaOH = Cacid * Vacid
158.32 * (18.76-0.14) = C acid * 25
C acid = 117.92 mM
The propagation of error for this problem, which is a multiplication is the concentration of the acid multiplied by the error divided by its respective value as shown in the equation below
error = 117.92 *
The answer is 0.03 mM of uncertainty.