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bija089 [108]
3 years ago
11

Why is feo named using a roman numeral, iron (ii) oxide, whereas cao named without a roman numeral, calcium oxide?

Chemistry
1 answer:
Hitman42 [59]3 years ago
7 0
<span>Answer: Some metals have the ability to form differently charged ions. For example, iron can form 2 + or 3 + ions. If you simply gave the name iron chloride, you would not know which charge the iron ion possessed. A Roman numeral is to indicate the charge of the iron. Iron ( II ) means the iron has a 2 + charge Iron ( III ) means that the iron has a 3 + charge So, iron ( II ) oxide would have a chemical formula of FeO . (The oxide ion has a 2 â’ charge to balance the 2 + of the iron to form a neutral compound.) Iron ( III ) oxide would have a chemical formula of Fe 2 O 3 (Here you need to find the common multiple of 6, so two iron ions with a 3 + charge will balance the charge of three oxide ions with a 2 + charge.)</span>
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1. The empirical formula of the hydrocarbon is CH₃

2. The molecular formula of the hydrocarbon is C₂H₆

<h3>How to determine the mass of Carbon </h3>
  • Mass of CO₂ = 1.47 g
  • Molar mass of CO₂ = 44 g/mol
  • Molar of C = 12 g/mol
  • Mass of C =?

Mass of C = (12 / 44) × 1.47

Mass of C = 0.4 g

<h3>How to determine the mass of H</h3>
  • Mass of compound = 0.5 g
  • Mass of C = 0.4 g
  • Mass of H = ?

Mass of H = (mass of compound) – (mass of C)

Mass of H = 0.5 – 0.4

Mass of H =0.1 g

<h3>1. How to determine the empirical formula </h3>
  • C = 0.4 g
  • H = 0.1 g
  • Empirical formula =?

Divide by their molar mass

C = 0.4 / 12 = 0.03

H = 0.1 / 1 = 0.1

Divide by the smallest

C = 0.03 / 0.03 = 1

H = 0.1 / 0.03 = 3

Thus, the empirical formula of the compound is CH₃

<h3>2. How to determine the molecular formula</h3>
  • Empirical formula = CH₃
  • Molar mass = 30 g/mol
  • Molecular formula =?

Molecular formula = empirical × n = mass number

[CH₃]n = 30

[12 + (3×1)]n = 30

15n = 30

Divide both side by 15

n = 30 / 15

n = 2

Molecular formula = [CH₃]n

Molecular formula = [CH₃]₂

Molecular formula = C₂H₆

Learn more about empirical formula:

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