d = 3 , a₁₂ = 40 and S
= 7775
In an arithmetic sequence the nth term and sum to n terms are
<h3>• a
= a₁ + (n-1)d</h3><h3>• S
=
[2a + (n-1)d]</h3><h3>
where d is the common difference</h3><h3>a₆ = a₁ + 5d = 22 ⇒ 7 + 5d = 22 ⇒ 5d = 15 ⇔ d = 3</h3><h3>a₁₂ = 7 + 11d = 7 +( 11× 3) = 7 + 33 = 40</h3><h3>S₁₀₀ =
[(2×7) +(99×3)</h3><h3> = 25(14 + 297) = 25(311)= 7775</h3>
9514 1404 393
Answer:
about 9.80 cm
Step-by-step explanation:
The length of half the segment (h) can be found from the Pythagorean theorem:
h² +5² = 7²
h² = 7² -5² = 49 -25 = 24
h = √24 = 2√6
This is half the segment length, so the whole segment length is ...
L = 2h = 2(2√6)
L = 4√6 ≈ 9.7980
The length of the segment is 4√6 ≈ 9.80 cm.
Answer:
Pls Help
I will mark as brainliest!!!!
which integer represents a golf score of 4 over par?
Step-by-step explanation:
I will mark as brainliest!!!!
which integer represents a golf score of 4 over par?Pls Help
I will mark as brainliest!!!!
which integer represents a golf score of 4 over par?
Answer:
the slope or rate of change is 8 over 6 or 4 over 3 4/3
First find the area of the parallelogram
Area of parallelogram = b x h
= 12 x 7
= 84
Then find area of kite
Area of kite = (xy)/2
= (7 x 12)/2
= 84/2
= 42
Now we are gonna subtract the area of the kite from the area of the parallelogram.
84 - 42 = 42
Therefore the area of the shaded region is 42.
