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3 years ago

Please help?? ??????

Mathematics

1 answer:

Deffense [45]3 years ago

5 0

The slope of your problem is -4/3

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#10

amm1812

Answer:

There are 3 green marbles in the box.

Step-by-step explanation:

15% = 0.15

To figure out how much 15% of 21 is, you must multipl the decimal form of the percentage by the whole number. This will give you how much of that number that percentage is.

0.15 * 21 = 3.15

But you can't have 0.15 of a marble, so you must round as well.

3 green marbles in the box.

3 0

3 years ago

The GCD(a, b) = 9, the LCM(a, b)=378. Find the least possible value of a+b.

denis-greek [22]

$\mathrm{gcd}(a,b)=9\implies9\mid a\text{ and }9\mid b\implies9\mid a+b$

which means there is some integer $k$ for which $a+b=9k$ .

Because $9\mid a$ and $9\mid b$ , there are integers $n_1,n_2$ such that $a=9n_1$ and $b=9n_2$ , and

$\mathrm{lcm}(a,b)=\mathrm{lcm}(9n_1,9n_2)=9\mathrm{lcm}(n_1,n_2)=378\implies\mathrm{lcm}(n_1,n_2)=42$

We have $42=2\cdot3\cdot7$ , which means there are four possible choices of $n_1,n_2$ :

1, 42
2, 21
3, 14
6, 7

which is to say there are also four corresponding choices for $a,b$ :

9, 378
18, 189
27, 126
54, 63

whose sums are:

387
207
153
117

So the least possible value of $a+b$ is 117.

6 0

3 years ago

What are the values of AB and DE in parallelogram ABCD? AB=? PLEASE HELP

GarryVolchara [31]

Answer:

AB=12

ED=6

Step-by-step explanation:

AB=CD=12

BC=AD=26

ED=26-20=6

5 0

2 years ago

Can someone answer this please

Alexxandr [17]

Answer:

Range: (-∞, 0]

General Formulas and Concepts:

Algebra I

Range is the set of y-values that are outputted by function f(x)

Step-by-step explanation:

When we graph the equation, we should see that our y-values span from -∞ to 0. Since 0 is a closed dot, it is inclusive in the range:

(-∞, 0] or y ≤ 0

4 0

3 years ago

Which is the inverse of the function f(x) = x2 − 4?

Rudiy27

The function is not one-to-one function, hence the inverse doesn't exist for the whole domain of the function. But if we restrict the domain to $x\in(-\infty,0]$ or $x\in[0,\infty)$ , then we can give the inverse.

$f(x)=x^2-4\\\\y=x^2-4\\\\x^2=y+4\\\\x=\sqrt{y+4} \vee x=-\sqrt{y+4}\\\\f^{-1}(x)=\sqrt{x+4}\vee f^{-1}(x)=-\sqrt{x+4}$

So, when $D_{f(x)}:x\in(-\infty,0]$ , the inverse is $f^{-1}(x)=-\sqrt{x+4}$ and when $D_{f(x)}:x\in[0,\infty)$ , the inverse is $f^{-1}(x)=\sqrt{x+4}$ .

7 0

3 years ago