Question

a gas has a volume of 590 mL at a temperature of 590 mL at a temperature of -55.0 degrees Celsius. What volume will the gas occupy at 30.0 degrees Celsius?

Answer 1

Answer: The volume that gas occupy will be 820.04mL.

Explanation:

To calculate the volume of the gas at different temperature, we will use the equation given by Charles' Law.

This law states that volume is directly proportional to the temperature of the gas at constant pressure and number of moles.

$V\propto T$

or,

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

where,

$V_1\text{ and }T_1$ are the initial volume and initial temperature of the gas.

$V_2\text{ and }T_2$ are the final volume and final temperature of the gas.

We are given:

$T(K)=273+T(^oC)$

$V_1=590mL\\T_1=-55^oC=218K\\V_2=?mL\\T_2=30^oC=303K$

Putting values in above equation:

$\frac{590}{218}=\frac{V_2}{303}\\\\V_2=820.04mL$

Hence, the volume that gas occupy will be 820.04mL.

Answer 2

According to Charles' Law, V1/T1=V2/T2
590 mL/-55.0 C=V2/30.0 C --> -10.7 mL/C=V2/30.0 C --> -321 mL=V2