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viva [34]
3 years ago
13

Identify and explain the process shown below. Name any two products obtained during this process and state their uses.

Chemistry
1 answer:
lapo4ka [179]3 years ago
5 0

Answer:

This is heating limestone

Explanation:

Process:

limestone is heated strongly. After a while, the limestone begins to go cloudy. Test tube is heated too much that it is beginning to  soften it. After removing limewater, test tube cools down, the pressure in the test tube drops and air pressure pushes the cold the liquid into the hot test tube with terrible result.

Products:

Limestone is also known as calcium carbonate and Limewater

Click on the link provided to show the video

https://youtu.be/RLL5rT_DeKc

or search heating calcium carbonate

you will find a video

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35

Because there’s 7 carbon atoms in every molecule of artificial sweetener

And if you have 5 molecules of that

7x5 =35
4 0
3 years ago
How many moles of potassium are contained in 449 g of<br> potassium?<br> pls help im so lost
e-lub [12.9K]

Answer:

449 (g K) / 39.1 (g/mol K) = 11.5 mol K

Explanation:

Potassium has atomic number 39.1

amount of K in 449g sample = 449/39.1 = 11.5 mol

4 0
2 years ago
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What substances make up water?
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The density of NO2 in a 4.50 L tank at 760.0 torr and 25.0 °C is ________ g/l.
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4 0
2 years ago
A chemical reaction is shown below:
BabaBlast [244]

Answer:

Mass = 8.46 g

Explanation:

Given data:

Mass of water produced = ?

Mass of glucose = 20 g

Mass of oxygen = 15 g

Solution:

Chemical equation:

C₆H₁₂O₆ + 6O₂     →   6H₂O + 6CO₂

Number of moles of glucose:

Number of moles = mass/molar mass

Number of moles = 20 g/ 180.16 g/mol

Number of moles = 0.11 mol

Number of moles of oxygen:

Number of moles = mass/molar mass

Number of moles = 15 g/ 32 g/mol

Number of moles = 0.47 mol

now we will compare the moles of water with oxygen and glucose.

               C₆H₁₂O₆           :            H₂O

                   1                   :              6

                 0.11                :           6/1×0.11 = 0.66

                   O₂               :            H₂O

                   6                   :              6

                 0.47                :           0.47

Less number of moles of water are produced by oxygen thus it will limit the yield of water and act as limiting reactant.

Mass of water produced:

Mass = number of moles × molar mass

Mass = 0.47 mol  ×18 g/mol

Mass = 8.46 g

8 0
2 years ago
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