Question

What volume of H2so4 Solution Cspecific gravity=-1.28 and strength =24.7% by mass) will be required to react completely with 125g ZnC032?
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Answer 1

The volume = 309.04 ml

Further explanation

Given

Specific gravity=-1.28 and strength =24.7% by mass of H₂SO₄

mass 125g of ZnC0₃

Required

The volume of H₂SO₄ Solution

Solution

Reaction

ZnCO₃ + H₂SO₄ → ZnSO₄ + CO₂ + H₂O

mol of ZnCO₃(MW=125.4 g/mol) :

$\tt mol=\dfrac{125}{125.4}=0.997$

From equation, mol ZnCO₃ : H₂SO₄= 1 : 1 so mol H₂SO₄=0.997

mass of H₂SO₄ (MW=98 g/mol) :

$\tt mass=mol\times MW=0.997\times 98=97.706~g$

mass of solution :

$\tt \dfrac{100}{24.7}\times 97.706=395.57~g$

Volume of solution :(density of solution=1.28 g/ml for the reference substance is water(density=1 g/ml)

$\tt V=\dfrac{395.57}{1.28}=309.04~ml$