Question is Incomplete, Complete question is given below.
Prove that a triangle with the sides (a − 1) cm, 2√a cm and (a + 1) cm is a right angled triangle.
Answer:
∆ABC is right angled triangle with right angle at B.
Step-by-step explanation:
Given : Triangle having sides (a - 1) cm, 2√a and (a + 1) cm.
We need to prove that triangle is the right angled triangle.
Let the triangle be denoted by Δ ABC with side as;
AB = (a - 1) cm
BC = (2√ a) cm
CA = (a + 1) cm
Hence,
Now We know that
So;
Now;
Also;
Now We know that
[By Pythagoras theorem]
Hence,
Now In right angled triangle the sum of square of two sides of triangle is equal to square of the third side.
This proves that ∆ABC is right angled triangle with right angle at B.
Unfortunately, Tashara, you have not provided enuf info from which to calculate the values of a and b. If you were to set <span>F(x)=x(x+a)(x-b) = to 0, then:
x=0,
x=-a
x=-b
but this doesn't answer your question.
Double check that you have shared all aspects of this question.</span>
Answer:
The polynomial will be P(x) = - 5 (x + 2)²(x - 3)
Step-by-step explanation:
The degree of the polynomial P(x) is 3 and it has zeros at x = - 2 with multiplicity 2 and at x = 3 with multiplicity 1.
Therefore, (x + 2)² and (x - 3) are the factors of the equation.
Let the polynomial is
P(x) = a(x + 2)²(x - 3) ........... (1)
Now, the polynomial passes through the point (2,80).
So, from equation (1) we gat,
80 = a(4)²(-1)
⇒ a = - 5
Therefore, the polynomial will be P(x) = - 5 (x + 2)²(x - 3) (Answer)
Answer:
1.
A: GI= 60
B: MH= 14
C: IK= 23
D: HI= 46
E: MG= 24
2.
A: TU= 38
B: VY= 17
C: UZ= 15
D: WV= 15
E: TV= 30
Step-by-step explanation:
This probally isnt all right but most of it most likely is.
