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3 years ago

A) a clockwise rotation of 270 degrees about the origin

Mathematics

1 answer:

8090 [49]3 years ago

7 0

Answer:

C. A reflection over the y-axis

Step-by-step explanation:

The correct answer would be choice "C" because first off, you can see that the shape hasn't grown/shrink. We can also see that it doesn't seemed to have rotated, otherwise it would be flipped in a certain direction. So, now we're left with a reflection over the y-axis/reflection over x-axis.

If the shape had reflected over the x-axis, it would be in the lower quadrants of the graph, since it would be flipped over a horizontal line. But instead, the shape has flipped to the left, making it a reflection over the y-axis.

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nydimaria [60]

Answer:

shifted left 7 & shifted down 3

Step-by-step explanation:

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3 years ago

What's the area of the square?

mart [117]

Your answer is D. 25.25

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3 years ago

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<img src="https://tex.z-dn.net/?f=prove%20that%5C%20%20%5Ctextless%20%5C%20br%20%2F%5C%20%20%5Ctextgreater%20%5C%20%5Cfrac%20%7B

inysia [295]

$\large \bigstar \frak{ } \large\underline{\sf{Solution-}}$

Consider, LHS

$\begin{gathered}\rm \: \dfrac { \tan \theta + \sec \theta - 1 } { \tan \theta - \sec \theta + 1 } \\ \end{gathered}$

We know,

$\begin{gathered}\boxed{\sf{ \:\rm \: {sec}^{2}x - {tan}^{2}x = 1 \: \: }} \\ \end{gathered} \\ \\ \text{So, using this identity, we get} \\ \\ \begin{gathered}\rm \: = \:\dfrac { \tan \theta + \sec \theta - ( {sec}^{2}\theta - {tan}^{2}\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered}$

We know,

$\begin{gathered}\boxed{\sf{ \:\rm \: {x}^{2} - {y}^{2} = (x + y)(x - y) \: \: }} \\ \end{gathered} \\$

So, using this identity, we get

$\begin{gathered}\rm \: = \:\dfrac { \tan \theta + \sec \theta - (sec\theta + tan\theta )(sec\theta - tan\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered}$

can be rewritten as

$\begin{gathered}\rm\:=\:\dfrac {(\sec \theta + tan\theta ) - (sec\theta + tan\theta )(sec\theta -tan\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:\dfrac {(\sec \theta + tan\theta ) \: \cancel{(1 - sec\theta + tan\theta )}} { \cancel{ \tan \theta - \sec \theta + 1} } \\ \end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:sec\theta + tan\theta \\\end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:\dfrac{1}{cos\theta } + \dfrac{sin\theta }{cos\theta } \\ \end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:\dfrac{1 + sin\theta }{cos\theta } \\ \end{gathered}$

<h2>Hence,</h2>

$\begin{gathered} \\ \rm\implies \:\boxed{\sf{ \:\rm \: \dfrac { \tan \theta + \sec \theta - 1 } { \tan \theta - \sec \theta + 1 } = \:\dfrac{1 + sin\theta }{cos\theta } \: \: }} \\ \\ \end{gathered}$

$\rule{190pt}{2pt}$

5 0

2 years ago

How many whole sandwiches can be made with 2 pounds of cheese if each sandwich has 3 ounces of cheese on it

mariarad [96]

10 whole sandwiches can be made with 2 pounds of cheese if each sandwhich has 3 ounces of cheese on it.

2 pounds = 32 ounces

32/3 = 10.67

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3 years ago

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The function f(x) = x2 + 10x – 3 written in vertex form is f(x) = (x + 5)2 – 28. What are the coordinates of the vertex?

Alexxandr [17]

Vertex form uses the following formula:

$y = a(x-h)^2 + k$

Identify the values of h and k in your function:

$(x+5)^2 - 28$
$h = -5, k = -28$

The vertex is found with the following point:

$(h,k)$
$\text{Vertex: (-5, -28)}$

The vertex will be found at (-5, -28).

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3 years ago