Answer:
Step-by-step explanation:
A binary string with 2n+1 number of zeros, then you can get a binary string with 2n(+1)+1 = 2n+3 number of zeros either by adding 2 zeros or 2 1's at any of the available 2n+2 positions. Way of making each of these two choices are (2n+2)22. So, basically if b2n+12n+1 is the number of binary string with 2n+1 zeros then your
b2n+32n+3 = 2 (2n+2)22 b2n+12n+1
your second case is basically the fact that if you have string of length n ending with zero than you can the string of length n+1 ending with zero by:
1. Either placing a 1 in available n places (because you can't place it at the end)
2. or by placing a zero in available n+1 places.
0 ϵ P
x ϵ P → 1x ϵ P , x1 ϵ P
x' ϵ P,x'' ϵ P → xx'x''ϵ P
Answer:
6 is the domain because it is always the x value while range is the y value.
Answer:
The initial value in the word problem is the output value when input value is set to zero.
Step-by-step explanation:
- In the question, it is given that a problem uses a linear function.
- It is required to explain how to interpret the initial value in a word problem.
- In order to find the initial value in a world problem, find the output value when input value is set to zero.
- If the initial value is marked as b for a linear function f(x), find it as follow,
(If It's a number like this: 8/9 then it's a fraction)
Answer:
<h2><em><u>
9. -2/6</u></em></h2><h2><em><u>
10. -6/-10</u></em></h2><h2><em><u>
11. 3/4</u></em></h2>
Step-by-step explanation:
Yay, I love doing these!
9.} 6 - 8 and 4- -2= -2/6
10.} 3 - 9 and -1 - 9= -6/-10
11.} -1 - -7 and 5 - -3= 6/8 simplify it by 2= 3/4
Step-by-step explanation:
(5√2-4√3)(5√2-4√3)=
(5√2-4√3)^2=(5√2)^2+(4√3)^2-2(5√2)(4√3)
=25*2+16*3-10√2*4√3
=50+48-10√2*4√3
=98-10√2*4√3 is the answer
