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3 years ago

Can yall help, whoever answers correctly will get brainllest!

Mathematics

1 answer:

melamori03 [73]3 years ago

4 0

Answer:

A,C,D

Step-by-step explanation:

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What is the interpret of the equation 2x+1. 5y=30

Setler [38]

The intercept would be 5 Y if you acually solve that equation

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3 years ago

Simplify the product using distributive property (2x-5)(x+3) show work

coldgirl [10]

Use the FOIL method
First, Outside, Inside, Last
(2x -5)(x + 3)

2x(x) = 2x²
2x(3) = 6x
-5(x) = -5x
-5(3) = -15

2x² + 6x - 5x - 15

simplify

2x² + 6x - 5x - 15

2x² + x - 15

2x² + x - 15 is your answer

hope this helps

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3 years ago

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What's the value that could be added to 2/5 to make the sum greater than 1/2

Svetlanka [38]

The value that could me added to 2/5 that could make the sum greater than 1/2 is 1/5 possibly. Hope this helps! :)

<h2>-CloutAnswers</h2>

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3 years ago

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Algebra problem!!! Please help me!!!

zmey [24]

Good morning Brainiac

x+y = 13

1/2 x +y = 10

We gonna solve x+y=13 for x

So let's start by adding -y to both sides

x+y -y = 13-y

x= -y +13

Now substitute -y+13 for x in 1/2 x +y=10

1/2 x +y = 10

1/2 (-y+13)+y=10

1/2 y + 13/2 = 10

Now add -13/2 to both sides

1/2 y+13/2 -13/2 = 10- 13/2

1/2 y = 7/2

Now eliminate the common denominator which is 2

y = 7

Now we have the value for y, so lets find the value for x by substitute 7 for y in x= -y+13

x= -y+13

x= -7 + 13

x= 6

Answer : (6,7)

The answer is B

I hope that's help and if you have questions please let me know :)

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3 0

3 years ago

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Find the mass and the center of mass of a wire loop in the shape of a helix (measured in cm: x = t, y = 4 cos(t), z = 4 sin(t) f

Sholpan [36]

Answer:

Mass

$\sqrt{17}(\displaystyle\frac{8\pi^3}{3}+32\pi)$

Center of mass

Coordinate x

$\displaystyle\frac{(\displaystyle\frac{(2\pi)^4}{4}+32\pi)}{(\displaystyle\frac{8\pi^3}{3}+32\pi)}$

Coordinate y

$\displaystyle\frac{16\pi}{(\displaystyle\frac{8\pi^3}{3}+32\pi)}$

Coordinate z

$\displaystyle\frac{-16\pi}{(\displaystyle\frac{8\pi^3}{3}+32\pi)}$

Step-by-step explanation:

Let W be the wire. We can consider W=(x(t),y(t),z(t)) as a path given by the parametric functions

x(t) = t

y(t) = 4 cos(t)

z(t) = 4 sin(t)

for 0 ≤ t ≤ 2π

If D(x,y,z) is the density of W at a given point (x,y,z), the mass m would be the curve integral along the path W

$m=\displaystyle\int_{W}D(x,y,z)=\displaystyle\int_{0}^{2\pi}D(x(t),y(t),z(t))||W'(t)||dt$

The density D(x,y,z) is given by

$D(x,y,z)=x^2+y^2+z^2=t^2+16cos^2(t)+16sin^2(t)=t^2+16$

on the other hand

$||W'(t)||=\sqrt{1^2+(-4sin(t))^2+(4cos(t))^2}=\sqrt{1+16}=\sqrt{17}$

and we have

$m=\displaystyle\int_{W}D(x,y,z)=\displaystyle\int_{0}^{2\pi}D(x(t),y(t),z(t))||W'(t)||dt=\\\\\sqrt{17}\displaystyle\int_{0}^{2\pi}(t^2+16)dt=\sqrt{17}(\displaystyle\frac{8\pi^3}{3}+32\pi)$

The center of mass is the point $(\bar x,\bar y,\bar z)$

where

$\bar x=\displaystyle\frac{1}{m}\displaystyle\int_{W}xD(x,y,z)\\\\\bar y=\displaystyle\frac{1}{m}\displaystyle\int_{W}yD(x,y,z)\\\\\bar z=\displaystyle\frac{1}{m}\displaystyle\int_{W}zD(x,y,z)$

We have

$\displaystyle\int_{W}xD(x,y,z)=\sqrt{17}\displaystyle\int_{0}^{2\pi}t(t^2+16)dt=\\\\=\sqrt{17}(\displaystyle\frac{(2\pi)^4}{4}+32\pi)$

$\bar x=\displaystyle\frac{\sqrt{17}(\displaystyle\frac{(2\pi)^4}{4}+32\pi)}{\sqrt{17}(\displaystyle\frac{8\pi^3}{3}+32\pi)}=\displaystyle\frac{(\displaystyle\frac{(2\pi)^4}{4}+32\pi)}{(\displaystyle\frac{8\pi^3}{3}+32\pi)}$

$\displaystyle\int_{W}yD(x,y,z)=\sqrt{17}\displaystyle\int_{0}^{2\pi}4cos(t)(t^2+16)dt=\\\\=16\sqrt{17}\pi$

$\bar y=\displaystyle\frac{16\sqrt{17}\pi}{\sqrt{17}(\displaystyle\frac{8\pi^3}{3}+32\pi)}=\displaystyle\frac{16\pi}{(\displaystyle\frac{8\pi^3}{3}+32\pi)}$

$\displaystyle\int_{W}zD(x,y,z)=4\sqrt{17}\displaystyle\int_{0}^{2\pi}sin(t)(t^2+16)dt=\\\\=-16\sqrt{17}\pi$

$\bar z=\displaystyle\frac{-16\sqrt{17}\pi}{\sqrt{17}(\displaystyle\frac{8\pi^3}{3}+32\pi)}=\displaystyle\frac{-16\pi}{(\displaystyle\frac{8\pi^3}{3}+32\pi)}$

3 0

3 years ago