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timofeeve [1]
2 years ago
13

Find the area of the regular polygon​

Mathematics
1 answer:
gregori [183]2 years ago
8 0

Answer:To find the area of a regular polygon, all you have to do is follow this simple formula: area = 1/2 x perimeter x apothem. Here is what it means: Perimeter = the sum of the lengths of all the sides. Apothem = a segment that joins the polygon's center to the midpoint of any side that is perpendicular to that side.

Step-by-step explanation:

hope this helps

plez mark as brainlyest

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At which root does the graph of f(x) = (x – 5)3(x + 2)2 touch the x axis?
LuckyWell [14K]
We have that
f(x) = (x – 5)³(x + 2)²

we know that
<span>the roots can touch or cross the x axis

</span>The way you can tell if the graph is going to cross the x-axis or just touch the x-axis is by looking at the power of the factor.

(x - 5)³ has a power of 3 which is an ODD number. An ODD power means that the graph will cross through the x-axis.

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5 0
2 years ago
Question 1
storchak [24]

Answer:

x = 13.5

y = 7

(13.5,7)

what the solution means is that (13.5,7) would be the point at which the two lines, x+y=20.5 and x-y=6.5, would intersect

Step-by-step explanation:

x + y = 20.5

x - y = 6.5

if we add the two equations we get:

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x = 13.5

y = 20.5 - 13.5

y = 7

solution as an ordered pair:

(13.5,7)

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5 0
2 years ago
Two cones have their heights in the ratio 1 : 3 and the radius of their bases in the ratio 3 : 1, show that their volumes are in
Nuetrik [128]
<h2>\large\bold{\underline{\underline{Question:-}}}</h2>

Two cones have their heights in the ratio 1 : 3 and the radius of their bases in the ratio 3 : 1 show that their volumes are in the ratio 3 : 1.

<h2>\large\bold{\underline{\underline{Solution:-}}}</h2>

⇒ Ratio of heights of two cones = 1 : 3

⇒ Ratio of radius of their bases = 3 : 1

⇒ We know that V = 1/3πr²h

⇒ Ratio of their volume = V1 : V2

\underline{ \underline{ \sf{Let's \:  find  \: the  \: ratio  \: of \:  their  \: volumes:}}}

{ \implies{ \sf  {V _{1}  :  V_{2}}}}

{ \implies{ \sf{ \frac{1}{3} \pi \:  { r_{1}}^{2}  h_{1} :  \frac{1}{3}  \pi \:  { r_{2} }^{2}  h_{2}}}}

{ \implies{ \sf{ {r_{1}}^{2}  h_{1} :  { r_{2}}^{2} h_{2}}}}

{ \implies{ \sf{ \frac{ { r_{1} }^{2} }{ { r_{2} }^{2} }  :  \frac{ h_{2} }{ h_{1} } }}} \\

{ \implies{ \sf{ \frac{ {3}^{2} }{ {1}^{2} }  :  \frac{3}{1} }}} \\

{ \implies{ \sf{ \frac{9}{1} :  \frac{3}{1}  }}} \\

{ \implies{ \sf{3 : 1}}} \\

{ \therefore{ \sf{ \green{Ratio  \: of  \: their \:  volumes = 3 : 1}}}}

4 0
3 years ago
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