Just factorize the polynomial and you will get (x-2)(x-10) its roots are +2 and +10 and the multiplicities are +4 root of multiplicity 1, and +10 root of multiplicity 1.
32.102,32.94,33.6,34.039,<span>34.198 </span>
The equation would be (3+√-16)(6-√-64)
A negative square root can not be a real number, meaning that we have to use the imaginary number.
(3+4i)(6-8i)
How to multiply imaginary numbers...
Treat this like an equation looking like (x-a)(y-b)
Use FOIL
(3+4i)(6-8i)
= 18-24i+24i-32i²
= 18-32i² (i²= -1 because i= √-1)
= 18- (-32)
= 18 + 32
= 50
Answer: see proof below
<u>Step-by-step explanation:</u>
Given: A + B + C = π and cos A = cos B · cos C
scratchwork:
A + B + C = π
A = π - (B + C)
cos A = cos [π - (B + C)] Apply cos
= - cos (B + C) Simplify
= -(cos B · cos C - sin B · sin C) Sum Identity
= sin B · sin C - cos B · cos C Simplify
cos B · cos C = sin B · sin C - cos B · cos C Substitution
2cos B · cos C = sin B · sin C Addition
Division
2 = tan B · tan C

<u>Proof LHS → RHS</u>
Given: A + B + C = π
Subtraction: A = π - (B + C)
Apply tan: tan A = tan(π - (B + C))
Simplify: = - tan (B + C)

Substitution: = -(tan B + tan C)/(1 - 2)
Simplify: = -(tan B + tan C)/-1
= tan B + tan C
LHS = RHS: tan B + tan C = tan B + tan C 
N=0 is the answer for this problem