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3 years ago

Buying a car

Mathematics

2 answers:

____ [38]3 years ago

7 0

Answer:

16,000

Step-by-step explanation:

20,000 x .20 = 4,000

20,000 - 4,000 = 16,000

Murljashka [212]3 years ago

6 0

Answer: 16,000$

Step-by-step explanation:

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Write 2 x 10^-5<br> in standard notation.

tamaranim1 [39]

I think the answer should be 0.00002

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2 years ago

What is the equation of a line that is perpendicular to −x+2y=4 and passes through the point (−2, 1) ? Enter your equation in th

ANTONII [103]

Perpendicular lines have slopes that multiply to get -1
y=mx+b is the slope intercept equation
m=slope

so get into y=mx+b form
-x+2y=4
solve for y
add x both sides
2y=x+4
divide by 2 both sides
y=(1/2)x+2
the slope is 1/2

perppendicular line slope multiplies to -1
1/2 times what=-1
times 2/1 both sides
what=-2/1=-2

y=-2x+b
find b
we are given a point is (-2,1)
when x=-2, y=1
1=-2(-2)+b
1=4+b
minus 3 both sides
-3=b

so the equation is
y=-2x-3

your teacher might want it in standard form (ax+by=c) so
add 2x both sides
2x+y=-3 is an equation

so y=-2x-3 is correct (slope intercept form)
2x+y=-3 is also correct (standard form)

6 0

2 years ago

Solve either of the correct equations using any method. Round to the nearest whole number d= Days

galina1969 [7]

Where is the question m8?

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2 years ago

Read 2 more answers

Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre

tatiyna

Answer:

The product of $3a^2.2a^3\\$ is $6a^6$

Step-by-step explanation:

We need to find the product of $3a^2.2a^3\\$

Using the exponent rule: $a^m. a^n = a^{m*n}$

So,

$3a^2.2a^3\\$

Applying above rule:

$3.2 (a^{2*3})\\$

$6a^6$

So, the product of $3a^2.2a^3\\$ is $6a^6$

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2 years ago

Radioactive Waste The rate at which radioactive waste is entering the atmosphere at time t is decreasing and is given by Pe^-kt,

Dmitry_Shevchenko [17]

Answer:

$\displaystyle{\int^{\infty}_0 {50e^{-0.04t}}\, dt}=1250$

Step-by-step explanation:

Given:

$T =\displaystyle{\int^{\infty}_0 {Pe^{-kt}} \, dt}$

where,

T = total amount of waste

P = 50, the initial rate

k = 0.04

t = time

$T =\displaystyle{\int^{\infty}_0 {50e^{-0.04t}} \, dt}$

now we need to solve this integral!

$T =\displaystyle{50\int^{\infty}_0 {e^{-0.04t}} \, dt}$

$T = \left|50\left(\dfrac{e^{-0.04t}}{-0.04}\right)\right|^{\infty}_0$

$T = \left|-1250e^{-0.04t}\right|^{\infty}_0$

$T = (-1250e^{-0.04(\infty)})-(-1250e^{-0.04(0)})$

when any number has a power of negative infinity it is 0. because: $a^-{\infty} = \dfrac{1}{a^{\infty}} = \dfrac{1}{\infty} = 0$ , like something being divided by a very large number!

$T = (-1250(0))-(-1250e^0)$

$T = 1250$

this is the total amount of waste

6 0

2 years ago