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3 years ago

SOMEONE PLEASE HELP ME! I've been stuck on this for over 3 hours and i really need help! I'm offering 40 points!

Mathematics

2 answers:

Ne4ueva [31]3 years ago

4 0

Answer:

$x\geq 8.6$

Step-by-step explanation:

This problem requires subtraction, then division.. The first step is to add 9.5 to each side of the inequality. This isolates 6x on one side and makes the equation easier to understand:

$-9.5+9.5+6x\geq 42.1+9.5\\6x\geq 51.6$

Next, you need to divide each side by 6 to get your answer:

$\frac{6x}{6}\geq \frac{51.6}{6} \\x\geq 8.6$

As a little bonus tip, if you ever end up dividing each side by a negative number, you MUST reverse the sign.

yawa3891 [41]3 years ago

4 0

Answer:

x≥8.6

Step-by-step explanation:

-9.5+6x≥42.1

Add 9.5 to cancel out the left hand side

6x≥42.1+9.5

6x≥51.6

Divide by 6.

x≥8.6

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The mean height of an adult giraffe is 18 feet. Suppose that the distribution is normally distributed with standard deviation 0.

Klio2033 [76]

Answer:

1. the probability that giraffe will be shorter than 17 feet tall is equal to 0.1056

2. the probability that a randomly selected giraffe will be between 16 and 19 feet tall is equal to 0.8882

3. the the 90th percentile for the height of giraffes is 19.024

Step-by-step explanation:

To calculate the probability that a giraffe will be shorter than 17 feet tall, we need to standardize 17 feet as:

$z=\frac{x-m}{s}$

Where x is the height of the adult giraffe, m is the mean and s is the standard deviation, so 17 feet is equivalent to:

$z=\frac{17-18}{0.8}=-1.25$

Now, the probability that giraffe will be shorter than 17 feet tall is equal to P(z<-1.25). Then, using the standard normal distribution table, we get that:

$P(z$

At the same way, 16 and 19 feet tall are equivalent to:

$z=\frac{16-18}{0.8}=-2.5\\z=\frac{19-18}{0.8}=1.25$

So, the probability that a randomly selected giraffe will be between 16 and 19 feet tall is equal to:

$P(-2.5$

Finally, to find the the 90th percentile for the height of giraffes, we need to find the value z that satisfy:

$P(Z$

Now, using the standard normal distribution table we get that z is equal to 1.28. Therefore, the height x of the giraffes that is equivalent to 1.28 is:

$z=\frac{x-m}{s} \\1.28=\frac{x-18}{0.8} \\x=(1.28*0.8)+18\\x=19.024$

it means that the the 90th percentile for the height of giraffes is 19.024

4 0

3 years ago

Solve 2x+3y=5 and 4x-y=17 using the method of elimination

liberstina [14]

I did it out on paper if you needed to show work. But y is -1 and x is 1

5 0

2 years ago

Read 2 more answers

Which expression is equivalent to (5.4x10^10) (3.3x10^21)?

natta225 [31]

Although, here are no expressions ! it's an incomplete question. So, showing the answer with general simplification $17.82(10^{31})$ .

<u>Step-by-step explanation:</u>

We have the expression as (5.4x10^10) (3.3x10^21) which can be further simplified as :

⇒(5.4x10^10) (3.3x10^21)

⇒ $(5.4(10^{10})(3.3(10^{21})$

keep the power terms together and numbers to simply. Hence, we get as below

⇒ $(5.4(3.3))(10^{21}.10^{10})$

⇒ $(17.82)(10^{21+10)})$

By solving the above, we get final simplified answer as

⇒ $17.82(10^{31})$

Although, here are no expressions ! it's an incomplete question . You may match $17.82(10^{31})$ to the listed options wherever!

4 0

3 years ago

4) find p (-1.2

eimsori [14]

Answer:

Step-by-step explanation:

5 0

3 years ago

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The cost of a lack has increased by 30% to £65. Work out the original price

Sveta_85 [38]

Cost of lack increased by 30%

new cost of lack will be = 100% + 30% = 130%

We are given that new cost = £65

Thus 130% of original cost = 65

100% of original cost = 65 × 100/130 = £50

Thus original price was £50

7 0

3 years ago