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Wewaii [24]
4 years ago
11

If the circumference of the circle is 72 what is the minor arc of a 60 degree angle

Mathematics
1 answer:
telo118 [61]4 years ago
6 0
The circumference involves 360 degrees.
60 degrees is one sixth of the circle (60/360)
So, one sixth of 72 is 12.


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What is the range of y equals square root of x +7+5?
Elodia [21]

The range of a function are the dependent variables for which the function exists. The range of the function will be y ≥ 5

<h3>Range of a function</h3>

The range of a function are the dependent variables for which the function exists

Given the function below;

f(x) = √x+7 + 5

The function can only exist for values less than or equal to -7 that is x ≤ -7.

Substitute

f(-7) =  √-7+7 + 5

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8 0
2 years ago
Last one lol please help!!!
Mekhanik [1.2K]

Answer:

(C) 50π

Step-by-step explanation:

For this problem, we need to find a way to relate the inner circle, to the square, to the outer circle.

Given that we know the area of a circle is πr^2, and our inner circle has a area of 25π, we can find the radius.

25π = πr^2

25 = r^2

5 = r

Note, that the diameter of the inner circle is parallel to the side of the square, meaning that the diameter of the inner circle is the length of the side of the square.

diameter = 2 * radius

d = 2 * 5 = 10.

Now that we know the value of the side of the square, we can find the length of the diagonal of the square, which is the diameter of the outer circle.

Using the properties of the 45-45-90 right triangle, we can say that the diagonal of the square is the length of the side times sqrt(2).

Outer_Diameter = 10 * sqrt(2)

Now to find the outer area, we need the formula for the area of a circle.  Note that the diameter is twice the radius, so we will simply divide by 2.

A = πr^2

A = π * [ ( 10 * sqrt(2) ) / 2 ]^2

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So the area of the outer circle is 50π.

Cheers.

5 0
3 years ago
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