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vredina [299]
3 years ago
13

There are 446 highlighters in a carton there are 38 cartons. What is the total amount of highlighters in all Carton. Please show

you're work thank you and answer this right ok
Mathematics
2 answers:
Kisachek [45]3 years ago
8 0
You would do 38 times 446 which equals 16056
Luda [366]3 years ago
3 0
Firdt of all, we know that there are 446 highlighters in a carton which means that each carton has 446 highlighters in it. Also, we know that there are 38 cartons in total. To find the answer, I will use tree diagram:
446 highlighters in 1 carton
x(highlighters) in 38 cartons
Steps:
Use cross multiply
x(1)=446(38)
x=16948 highlighters. As a result, there are 16948 highlighters in 38 cartons. Hope it help!
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REY [17]

Step-by-step explanation:

a.

y =  |x - 1|  + 2

b.

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7 0
3 years ago
The circumference of a circle is 50.24 centimeters. What is the diameter of the circle?
Vika [28.1K]
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3 years ago
An agricultural field trial compares the yield of two varieties of tomatoes for commercial use – one is the common variety used
miv72 [106K]

Answer:

p-value 0.0124

Step-by-step explanation:

Hello!

In this experiment, 10 plots were randomly sampled and each plot was divided in a half, one half was planted with the common variety of tomato and the other half was planted with the new hybrid variety. At harvest time it was measured the pounds per plant harvested and the variable difference was established. This study variable is defined as the difference between the pounds per plant of the hybrid variety minus the pound per plant of the common variety. Symbolized: Xd: Xnew - Xcommon.

The purpose of this experiment is to test whether there is a difference between the yield of both species. This is a classic example of a paired test, in which you want to put two dependent samples to test. The easiest way to recognize this type of test, if it is not specified in the problem, is that both variables are measured in the same sampling unit. In this case, the sampling unit is "one plot" that was divided and both verities of tomatoes were planted on it.

This test is also called "paired samples T-test" and as a statistic, you have to use the Student t.

The data given is:

sample: 10 plots

sample mean: Xd[bar]: 1.05ppp

sample standard deviation Sd: 1.23ppp

If the hybrid has a higher yield, that would mean that the difference between them would be positive if the difference is positive, its safe to assume that the population mean of the difference will be positive as well. Symbolically: μd>0

With this, you can state the hypothesis as:

H₀:μd≤0

H₁:μd>0

α: 0.05

t=<u> Xd[bar] - μd</u> ~ t_{n-1}

       Sd/n

tt_{obs}= (1.05 - 0) / (1.23/√10) = 2.69

This is a one-tailed test with critical value t_{9;0.95} = 1.83

the p-value for this test is also one tailed.

p(t_{9}≥2.69) = 1-P(t_{9}<2.69) = 1 - 0.9876 = 0.0124

The decision is to reject the null hypothesis.

I hope it helps!

5 0
3 years ago
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allsm [11]

Answer:

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Step-by-step explanation:

8 0
3 years ago
How can I answer this question?
stiv31 [10]
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7 0
4 years ago
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