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QveST [7]
3 years ago
15

the relationship between money earned and hours worked is linear. joe computes the slope between (4, 30) and (12, 90), then comp

utes the slope between (4, 30) and (10, 75). how do the two slopes compare?
Mathematics
2 answers:
julia-pushkina [17]3 years ago
6 0
Slope = rise/run =[y2-y1]/[x2-x1]

1) slope = [90 - 30] / [12 - 4] = 60 / 8 = 15/2

2) slope = [75 - 30] / [10 - 4] = 45 / 6 = 15 / 2

The slopps are equal.
mylen [45]3 years ago
3 0

Answer: The slopes are equal.

The points are representing the same line.

Step-by-step explanation:

We know that the slope between points (a,b) and (c,d) is given by :-

m=\dfrac{d-b}{c-a}

The slope between the points (4,30)  and (12,90) will be

m_1=\dfrac{90-30}{12-4}=\dfrac{60}{8}=\dfrac{15}{2}

The slope between the points (4,30) and (10,75) will be

m_2=\dfrac{75-30}{10-4}=\dfrac{45}{6}=\dfrac{15}{2}

\Rightarrow\ m_1=m_2

We know that if the slopes are equal then the lines are parallel.

But they have one point common (4,30) so it cannot be parallel, they ust be same line .

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Does the relation {(-2,2), (-7,1), (-3,9), (-8,4), (-9,5), (-6,8)) represent
Gelneren [198K]

Answer:

Yes

Step-by-step explanation:

This does represent a function because every x-value only goes to one y-value.

7 0
3 years ago
The density of mercury is 13.6 grams per cubic centimeter. Complete the steps for converting 13.6 g/cm^3 to kg/m^3
Mama L [17]

1 cubic meter = 100 cm * 100 cm * 100 cm = 1 x 10^6 cc

1 kilogram = 1,000 grams

13.6 g / cc

If we had a cubic meter of mercury, its mass would be (or it would "weigh") 13.6 * 1,000,000 = 13,600,000 grams or 13,600 kilograms.

And so its density would be 13,600 kg / cubic meter.


4 0
3 years ago
The volume V of an ice cream cone is given by V = 2 3 πR3 + 1 3 πR2h where R is the common radius of the spherical cap and the c
Nuetrik [128]

Answer:

The change in volume is estimated to be 17.20 \rm{in^3}

Step-by-step explanation:

The linearization or linear approximation of a function f(x) is given by:

f(x_0+dx) \approx f(x_0) + df(x)|_{x_0} where df is the total differential of the function evaluated in the given point.

For the given function, the linearization is:

V(R_0+dR, h_0+dh) = V(R_0, h_0) + \frac{\partial V(R_0, h_0)}{\partial R}dR + \frac{\partial V(R_0, h_0)}{\partial h}dh

Taking R_0=1.5 inches and h=3 inches and evaluating the partial derivatives we obtain:

V(R_0+dR, h_0+dh) = V(R_0, h_0) + \frac{\partial V(R_0, h_0)}{\partial R}dR + \frac{\partial V(R_0, h_0)}{\partial h}dh\\V(R, h) = V(R_0, h_0) + (\frac{2 h \pi r}{3}  + 2 \pi r^2)dR + (\frac{\pi r^2}{3} )dh

substituting the values and taking dx=0.1 and dh=0.3 inches we have:

V(R_0+dR, h_0+dh) =V(R_0, h_0) + (\frac{2 h \pi r}{3}  + 2 \pi r^2)dR + (\frac{\pi r^2}{3} )dh\\V(1.5+0.1, 3+0.3) =V(1.5, 3) + (\frac{2 \cdot 3 \pi \cdot 1.5}{3}  + 2 \pi 1.5^2)\cdot 0.1 + (\frac{\pi 1.5^2}{3} )\cdot 0.3\\V(1.5+0.1, 3+0.3) = 17.2002\\\boxed{V(1.5+0.1, 3+0.3) \approx 17.20}

Therefore the change in volume is estimated to be 17.20 \rm{in^3}

4 0
3 years ago
Help me please :) thanks
Fiesta28 [93]

Answer:

20 and 90

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Dr. Betz, a vet, is running a free rabies clinic. He estimates that it will take him 12 minutes for each animal he treats. Dr. B
Olin [163]

Answer:

equation: y = 12x

Dr. Betz worked for 8 hours.

Step-by-step explanation:

To write the equation we'll use the form y = mx, where y represents the amount of time the Doctor worked, m is the amount of minutes it takes to treat each animal, and x is how many animals have been treated. We know the value of m is 12, so let's put that into the equation:

y = 12x

Now we have our equation. We can use it to see how long Dr. Betz worked. He treated a total of 40 animals - 20 including the shaggy dog, and 20 after the shaggy dog. let's replace x with 40:

y = 12(40)

Now solve:

y = 480

Dr. Betz worked for 480 minutes. There are 60 minutes in an hour. Divide 480 by 60 to find out how many hours Dr. Betz worked for:

480/60 = 8

Dr. Betz worked for 8 hours.

7 0
3 years ago
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