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Arte-miy333 [17]
3 years ago
14

I need to know the answer

Mathematics
1 answer:
Rainbow [258]3 years ago
6 0
Make the mixed number improper ( multiply whole number by denomentaor then add that number to the numerator and put it over the orignial denominator) to get this
(15/2)/(21/4)=x/9
we know that a/b/c/d = a/d * d/c
so 15/2*4/21=60/42=x/9
simplify
30/21=x/9
10/7=x/9
10/9*9/1 (10/9*9) =x
90/9=x
10=x
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Which of the following is an irrational number?
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The correct answer is D <span>9.87 times 10 to the 4</span>
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3 years ago
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The height of a triangle is 5 cm shorter than its base. If the area of the triangle is 25 cm2, find the height of the triangle.
Olin [163]

Answer:

h = 5\ cm

Step-by-step explanation:

Let's call B at the base of the triangle and call h at the height of the triangle. Then we know that:

The height of a triangle is 5 cm shorter than its base. This means that:

h = B-5.

 The area of the triangle is 25 cm²

By definition the area of a triangle is:

A = 0.5Bh

For this triangle we know that A = 25\ cm^2 and h = B-5. We substitute these values in the equation and solve for B.

25 = 0.5B (B-5)

0.5B ^ 2-\frac{5}{2}B-25 = 0

Now we use the quadratic formula to solve the equation.

For an equation of the form ax ^ 2 + bx + c = 0 the quadratic formula is:

B=\frac{-b\±\sqrt{b^2-4ac}}{2a}

In this case note that:  a=0.5,\ \ b=-\frac{5}{2}\ \ c=-25

Then:

B=\frac{-(-\frac{5}{2})\±\sqrt{(-\frac{5}{2})^2-4(0.5)(-25)}}{2(0.5)}

B=\frac{\frac{5}{2}\±\sqrt{\frac{25}{4}+50}}{1}

B=\frac{5}{2}\±\frac{15}{2}

The solutions are:

B_1=\frac{5}{2}+\frac{15}{2}=10

B_2=\frac{5}{2}-\frac{15}{2}=-5

For this problem we take the positive solution.

B=10\ cm

Now we substitute the value of B in the equation to find the height h

h = 10-5

h = 5\ cm

6 0
3 years ago
Multiply and simplify (x-9)(x-3)
Volgvan

Answer:

x2-12x+3

Step-by-step explanation:

=x(x-3)-9(x-3)

=x2-3x-9x+3

=x2-12x+3

7 0
3 years ago
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Age at BBM 2019 Question Group 'A Brief answer questions; 1. Integrate the following: S(ax? + 2bx + c)3/2(2xa + 2b) dx 2.
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If the integral is

\displaystyle \int (ax^2+2bx+c)^{3/2}(2ax+2b)\,\mathrm dx

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\displaystyle \int u^{3/2}\,\mathrm du = \frac25u^{5/2} + C

which in terms of <em>x</em> is

\boxed{\dfrac25(ax^2+2bx+c)^{5/2} + C}

4 0
2 years ago
<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B5%20%2B%20n%7D%7B4%7D%20%20%3D%20%20-%201" id="TexFormula1" title=" \frac{5 + n}{
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Answer:

n=   -9

Step-by-step explanation:

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