10y 5 +30y 3 −15y Factor out the gcf then simplify the polynomial
1 answer:
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For this case we must find an expression equivalent to:
So:
We expanded by moving 2 out of the logarithm:
By definition of logarithm properties we have to:
The logarithm of a product is equal to the sum of the logarithms of each factor:
The logarithm of a division is equal to the difference of logarithms of the numerator and denominator.
Then, rewriting the expression:
We apply distributive property:
Answer:
An equivalent expression is:
Answer:
and a₁ =30000 for n = 2,3,4,5,6, ......
Step-by-step explanation:
Doug has joined a job with a starting salary of $30000 per year.
Hence, if a₁ is the salary of Doug in the first year, then
a₁ =30000
Now, each year Doug will receive a raise of $3000 in his salary.
Hence, in the 2nd year, his salary(a₂) will become ( a₁ +3000) per year.
Again, in the 3rd year, his salary(a₃) will become ( a₂ +3000) per year.
Therefor, in the similar manner the recursive formula for his salary in each year will be given as and a₁ =30000 for n = 2,3,4,5,6, ...... {aₙ is the yearly salary of Doug in the nth year} (Answer)