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Neporo4naja [7]
3 years ago
8

Write an expression to find the perimeter of the rectangle below: 2x - 3y 3x - 1

Mathematics
1 answer:
LuckyWell [14K]3 years ago
4 0

Answer:

2(5x-3y-1)

Step-by-step explanation:

perimeter of a rectangle formula:

2l+2w

l=length(2x-3y)5x

w=width(3x-1)

2(2x-3y)+2(3x-1)

4x-6y+6x-2

10x-6y-2

2) all of these numbers have a gcf of 2 so lets divide this equation by 2:

2(5x-3y-1)

hope this helps!

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A) Find the value of 3x – 2 when x = 4<br>b) Find the value of 5x + 6 when x = -2​
Svetradugi [14.3K]

Answer: 10 and -4

Step-by-step explanation:

3x - 2 Plug in 4 for x

3(4) - 2 = 12 - 2 = 10

5x + 6. Plug in -2 for x

5(-2) + 6 = -10 + 6 = -4

8 0
3 years ago
Find the value of y. Round your answer to the nearest tenth.
ss7ja [257]
I think its supposed to be divide so i think C. would be the answer

7 0
3 years ago
Read 2 more answers
In a quality control test of parts manufactured at Dabco Corporation, an engineer sampled parts produced on the first, second, a
sammy [17]

Answer:

p value = 0.0174

Conclusion : we reject the null hypothesis

Step-by-step explanation:

Thinking step:

We need to perform a test to determine if the proportion of the good parts is the same for all three shifts at a significance level of \alpha = 0.05

Assumption : all the population for each or the three shifts is not equal.

Calculation:

Let p₁ be the sample of the first shift

     p₂ be the sample of the second shift

     p₃ be the sample of the third shift

According to the null hypothesis

H₀ = p₁ = p₂ = p₃

In other words, all the population sample proportions are equal.

Alternatively, we can assume that the three shift are not equal p₁ ≠ p₂ ≠ p₃

Tabulating and performing the \chi² test gives 8.10

degrees of freedom:

df = k - 1

   = 3 - 1 = 2

Thus the degree of freedom is 2

Solving using the MINITAB software gives: p = 0.174

The solution shows that the p value < level of significance, then p-value lies in the range 0.0174≤\alpha≤0.05

Therefore, we reject the null hypothesis based on the fact that the three shifts are not equal.

5 0
3 years ago
Find the area of the shaded region. ​
densk [106]

[1]

A1 = (h (a + b)) / 2

A1 = (21 (17 + 32)) / 2

A1 = (21 x 49) / 2

A1 = 1,029 / 2

A1 = 514.5 mm²

[2]

A2 = (b x h) / 2

A2 = (11 x 9) / 2

A2 = 99 / 2

A2 = 49.5 mm²

[3]

The area of the shaded region =

A1 - A2 =

514.5 mm² - 49.5 mm² =

465 mm²

The answer is 465 mm².

4 0
3 years ago
The line tangent to the graph of g(x) = x^{3}-4x+1 at the point (2, 1) is given by the formula
Usimov [2.4K]

well, about A and D, I just plugged the values on the slope formula of

\bf \begin{array}{llll} g(x)=x^3-4x+1\\ L(x) = 8(x-2)+1 \end{array} \qquad \begin{cases} x_1=1.9\\ x_2=2.1 \end{cases}\implies \cfrac{f(b)-f(a)}{b-a}

for A the values are 8.01 and 8.0, so indeed those "slopes" are close. \textit{\huge \checkmark}

for D the values are -2.25 and 8.0, so no dice on that one.

for B, let's check the y-intercept for g(x), by setting x = 0, we end up g(0) = 0³-4(0)+1, which gives us g(0) = 1.

checking L(x) y-intercept, well, L(x) is in slope-intercept form, thus the +1 sticking out on the far right is the y-intercept, so, dice. \textit{\huge \checkmark}

for C, well, the slope if L(x) is 8, since it's in slope-intercept form, the derivative of g(x) is g'(x) = 3x² - 4, and thus g'(0) = -4, so no dice.

for E, do they intercept at (2,1)?  well, come on now, L(x) is a tangent line to g(x), so that's a must for a tangent. \textit{\huge \checkmark}

for F, we know the slope of the line L(x) is 8, is g'(2) = 8?  let's check

recall that g'(x) = 3x² - 4, so g'(2) = 3(2)² - 4, meaning g'(2) = 8, so, dice. \textit{\huge \checkmark}

6 0
3 years ago
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