2.32x10^8. I'm in Honors Chemistry in high school, I just inputted this into a calculator which is easy. Otherwise you can just take them out of scientific notation and into standard form which is this:
(160000000)(5800000)/4000000=232000000. And then convert it back.
<span>Given:
AB = x + 16
BC = 4x + 11
AC= 77
We can safely assume that,
AB + BC = AC
x + 16 + 4x + 11 = 77
5x + 27 = 77
5x = 77 - 27
5x = 50
x = </span>
![\frac{50}{5}](https://tex.z-dn.net/?f=%20%5Cfrac%7B50%7D%7B5%7D%20)
x = 10
Hence,
AB = x + 16 = 10 + 16 = 26
Hence, proved.
Answer:
. It means AC is perpendicular to AB.
Step-by-step explanation:
Vertices of given triangle are A(−2, −2), B(5, −2), and C(−2,22).
Distance formula:
![d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D)
Using distance formula we get
![AB=\sqrt{(5-(-2))^2+(-2-(-2))^2}=\sqrt{7^2}=7](https://tex.z-dn.net/?f=AB%3D%5Csqrt%7B%285-%28-2%29%29%5E2%2B%28-2-%28-2%29%29%5E2%7D%3D%5Csqrt%7B7%5E2%7D%3D7)
![BC=\sqrt{(-2-5)^2+(22-(-2))^2}=\sqrt{7^2+24^2}=\sqrt{625}=25](https://tex.z-dn.net/?f=BC%3D%5Csqrt%7B%28-2-5%29%5E2%2B%2822-%28-2%29%29%5E2%7D%3D%5Csqrt%7B7%5E2%2B24%5E2%7D%3D%5Csqrt%7B625%7D%3D25)
![AC=\sqrt{(-2-(-2))^2+(22-(-2))^2}=\sqrt{24^2}=24](https://tex.z-dn.net/?f=AC%3D%5Csqrt%7B%28-2-%28-2%29%29%5E2%2B%2822-%28-2%29%29%5E2%7D%3D%5Csqrt%7B24%5E2%7D%3D24)
According to Pythagoras theorem
![hypotenuse^2=perpendicular^2+base^2](https://tex.z-dn.net/?f=hypotenuse%5E2%3Dperpendicular%5E2%2Bbase%5E2)
![(BC)^2=(AC)^2+(AB)^2](https://tex.z-dn.net/?f=%28BC%29%5E2%3D%28AC%29%5E2%2B%28AB%29%5E2)
Perpendicular = AC
Base = AB
It means AC is perpendicular to AB.
Hence proved.
Answer=24.49 I’m not 100% sure but I believe this is the answer :)
Hope it helps