Let x = his wage before his raise.
x + .25x = 343.75
1.25x = 343.75
x = $ 275.00 Was his wage before his raise
Answer:
A.

B. Yes, Pablo can buy 2 pair of pants and 4 shirts.
Step-by-step explanation:
A. Let x be the number of pairs of pants and y be the number of shirts.
We have been given that Pablo wants to purchase 6 additional clothing pieces for his wardrobe. We can represent this information as:

We are also told that each pair of pants costs $20 and each shirt costs $15. So the cost of x pairs of pants will be 20x and cost of y shirts will be 15y.
As Pablo wants to spend $100 on clothing, so we can represent this information as:

Therefore, the system of equation representing the given situation will be:


B. To find if Pablo can buy 2 pair of pants and 4 shirts we will substitute x=2 and y=4 in our both equations.





We can see that x=2 and y=4 satisfies our both equation, therefore, Pablo can buy 2 pair of pants and 4 shirts.
The question is incomplete. The complete question is :
The population of a certain town was 10,000 in 1990. The rate of change of a population, measured in hundreds of people per year, is modeled by P prime of t equals two-hundred times e to the 0.02t power, where t is measured in years since 1990. Discuss the meaning of the integral from zero to twenty of P prime of t, d t. Calculate the change in population between 1995 and 2000. Do we have enough information to calculate the population in 2020? If so, what is the population in 2020?
Solution :
According to the question,
The rate of change of population is given as :
in 1990.
Now integrating,

![$=\frac{200}{0.02}\left[e^{0.02(20)}-1\right]$](https://tex.z-dn.net/?f=%24%3D%5Cfrac%7B200%7D%7B0.02%7D%5Cleft%5Be%5E%7B0.02%2820%29%7D-1%5Cright%5D%24)
![$=10,000[e^{0.4}-1]$](https://tex.z-dn.net/?f=%24%3D10%2C000%5Be%5E%7B0.4%7D-1%5D%24)
![$=10,000[0.49]$](https://tex.z-dn.net/?f=%24%3D10%2C000%5B0.49%5D%24)
=4900





This is initial population.
k is change in population.
So in 1995,



In 2000,


Therefore, the change in the population between 1995 and 2000 = 1,163.
Okay, so first divide 336 / 12 to find out how many miles are driven on each gallon. 336 / 12 = 28 So the car travels 28 miles per gallon (mpg).
Then, divide 1,344 / 28 1,344 / 28 = 48
And there's your answer! D) 48 gallons