Let x and y be your two consecutive whole numbers
x < sqrt(142) < y
x^2 < 142 < y
So, we are looking for x and y such that x^2 < 142 and y^2 > 142.
The closest squared number to 142 is 144 = 12^2.
Next is 11^2 = 121.
11 and 12 are consecutive.
11^2 = 121 < 142 < 144 = 12^2
Thus, 11 and 12 are your numbers
<h2>x = 3</h2>
Step-by-step explanation:
Step 1 Use 3 to open the bracket
Step 2: Collect like terms and simplify
Step 3: Divide both sides by 7
Answer:
u = -2
Explanation:
Slope of the line can be calculated using the following rule:
slope = (y2-y1) / (x2-x1)
We are given :
slope = 1/8
point (u,-9) represent (x1,y1)
point (6,-8) represent (x2,y2)
Substitute with the givens in the above equation and solve for u as follows:
slope = (y2-y1) / (x2-x1)
1/8 = (-8--9) / (6-u)
1/8 = (1) / (6-u)
1* (6-u) = 1*8
6-u = 8
u = 6-8
u = -2
Hope this helps :)
Answer
55 divided by 5 = 11
Step by step explanation
Assume that we have 55 balls, we have to group 5 balls in each group.
How many group can we form?
The number of groups = 55/5 = 11
Use can see it in the picture.
We have to explain with pictorial method.
I have attached the figure.
Hope this will helpful.
Thank you.
Answer:
15 m, but it depends on your shape?
