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3 years ago

A liquid in the lab has a density of 1.24 g/cm3. What is the mass in grams of 254 ml of the liquid

Mathematics

1 answer:

Airida [17]3 years ago

5 0

Answer:

<h2>The answer is 314.96 g</h2>

Step-by-step explanation:

The mass of a substance when given the density and volume can be found by using the formula

<h3>mass = Density × volume</h3>

From the question

volume of liquid = 254 mL

Density = 1.24 g/cm³

The mass is

mass = 254 × 1.24

We have the final answer as

Hope this helps you

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Find the distance when y2=9, y1=13, x2=4, and x1=0.

Ket [755]

Answer:

Tthe distance between $\left(x_1,\:y_1\right)=\left(0,\:13\right)$ and $\left(x_2,\:y_2\right)=\left(4,\:9\right)$ will be:

$\mathrm{Distance\:between\:}\left(0,\:13\right)\mathrm{\:and\:}\left(4,\:9\right):\quad 4\sqrt{2}$

Step-by-step explanation:

Given the points

$\left(x_1,\:y_1\right)=\left(0,\:13\right)$

$\left(x_2,\:y_2\right)=\left(4,\:9\right)$

$\mathrm{Compute\:the\:distance\:between\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\quad \sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

$\mathrm{The\:distance\:between\:}\left(0,\:13\right)\mathrm{\:and\:}\left(4,\:9\right)\mathrm{\:is\:}$

$=\sqrt{\left(4-0\right)^2+\left(9-13\right)^2}$

$=\sqrt{4^2+4^2}$

$=\sqrt{4^2\cdot \:2}$

$\mathrm{Apply\:radical\:rule\:}\sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b},\:\quad \mathrm{\:assuming\:}a\ge 0,\:b\ge 0$

$=\sqrt{2}\sqrt{4^2}$

$\mathrm{Apply\:radical\:rule\:}\sqrt[n]{a^n}=a,\:\quad \mathrm{\:assuming\:}a\ge 0$

$=4\sqrt{2}$

Therefore, the distance between $\left(x_1,\:y_1\right)=\left(0,\:13\right)$ and $\left(x_2,\:y_2\right)=\left(4,\:9\right)$ will be:

$\mathrm{Distance\:between\:}\left(0,\:13\right)\mathrm{\:and\:}\left(4,\:9\right):\quad 4\sqrt{2}$

7 0

3 years ago

I need help ASAP anyone ???

Anna [14]

Answer: 141.7 ct

Step-by-step explanation: It's quite easy to notate this. Just move the decimal point two units to the right, and there's your notation!

8 0

3 years ago

Read 2 more answers

find the cost of carpeting the following rectangular rooms:a. Dimensions: 7.5m x 4.5m; Cost= $14.17/m^2b. Dimensions: 17 yd. x 1

Bezzdna [24]

Dimensions: 7.5m x 4.5m

Cost , x= $14.17/m^2.

The area of the rectangular room can be calculated as,

$\begin{gathered} A=7.5\times4.5 \\ =33.75m^2 \end{gathered}$

Now, the cost of carpeting the rectangular room is,

$\begin{gathered} C=xA \\ =14.17\times33.75 \\ =478.24\text{ } \end{gathered}$

Therefore, the cost of carpeting the room with dimensions 7.5m x 4.5m is $478.24.

Dimensions: 17 yd. x 12 yd.

Cost, x= $25/yd^2.

The area of the rectangular room can be calculated as,

$\begin{gathered} A=17\times12 \\ =204yd^2 \end{gathered}$

Now, the cost of carpeting the rectangular room is,

$\begin{gathered} C=xA \\ =25\times204 \\ =5100 \end{gathered}$

Therefore, the cost of carpeting the room with dimensions 17 yd. x 12 yd is $5100.

6 0

1 year ago

A lottery winner must choose between f(x) and g(x) for the distribution of winnings, where x equals the number of monthly paymen

FrozenT [24]

Answer:

Step-by-step explanation:

7 0

4 years ago

The perimeter of a rectangle is 42 inches if the width of the rectangle is 6 inches, what is the length?

Karo-lina-s [1.5K]

Answer:

15 inches

Step-by-step explanation:

Perimeter is 2l + 2w (or l+l+w+w)

Start by subtracting: 42 - 12. The 12 is from 2•6 for both width sides.

42-12=30

Divide 30 by 2 to find the length for one side. 30 ÷ 2 = 15

5 0

3 years ago