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MakcuM [25]
3 years ago
13

(Help needed ASAP I’m confused ) Solve the equation by using the distributive property first

Mathematics
2 answers:
Misha Larkins [42]3 years ago
4 0
I got the answer. Use Brainly
Nadusha1986 [10]3 years ago
4 0

Answer:

x=0

Step-by-step explanation:

simplify: 15(x-3) over 15 ( srry i dont know how to make that a fraction.)

3(2x-3)= 3x-9

3x-9=6x-9

move all terms containing x to the left side of the equation

-3x-9=-9

move all terms not containing x to the right side of the equation

-3x=0

divide both sides by -3 and simplify if needed

x=0

( hope this helped.)

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Alinara [238K]
I think the answer is 6 since u multiply them
8 0
3 years ago
Need an answer I need help?
SIZIF [17.4K]

Answer:

You need help or I need help?

Step-by-step explanation:

(I typed with a keyboard)

7 0
3 years ago
Complete the proof<br> Prove: UVY = UZW<br> A) AAS<br> B) ASA<br> C) SAS<br> D) SSS
puteri [66]

Answer:

B) ASA

Step-by-step explanation:

The ASA (Angle-Side-Angle) postulate states that if two angles and the included side of one triangle are congruent to two angles and the included side of another triangle, then the triangles are congruent. (The included side is the side between the vertices of the two angles)

In this case, angle U, side UY and angle Y are congruent to angle U, side UW and angle W

7 0
3 years ago
This is just the first pic of the problem I’m posting the second one right after this
ale4655 [162]

Answer:

A. rise = 4, run = 1, slope = 4

B. rise = 8, run = 2, slope = 4

C. A (Yes, they are equal because similar)

Step-by-step explanation:

i hope this is right

4 0
2 years ago
What is the area of a rectangle that has side lengths of 3/4 yard and 5/6 yard
Ahat [919]

We are asked to find the area of the rectangle that has side lengths of 3/4 yard and 5/6 yard.

We know that area of rectangle is width times length.

To find the area of the given rectangle we will multiply both side lengths as:

\text{Area of rectangle}=\text{Width}\times \text{Length}

\text{Area of rectangle}=\frac{3}{4}\text{ yard}\times\frac{5}{6}\text{ yard}

\text{Area of rectangle}=\frac{3}{4}\times\frac{5}{6}\text{ yard}^2

\text{Area of rectangle}=\frac{1}{4}\times\frac{5}{2}\text{ yard}^2

\text{Area of rectangle}=\frac{1\times5}{4\times2}\text{ yard}^2

\text{Area of rectangle}=\frac{5}{8}\text{ yard}^2

Therefore, the area of the given rectangle would be \frac{5}{8} square yards.

5 0
3 years ago
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