Whats 56753 ÷ 43 = ????????????????????????????????????????????

Mathematics

2 answers:

Bingel [31]3 years ago

7 0

The answer is 1,329.83721

dalvyx [7]3 years ago

6 0

Answer:

1,319.83721

Step-by-step explanation:

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Angle x has a measurement of

jarptica [38.1K]

Answer:

110

Step-by-step explanation:

x=110 due to congruent angle

(suggest u to draw 2 straight lines and observe differences and similarities of the 4 angles)

7 0

2 years ago

Using the 45°-45°-90° triangle theorem, find the value of h, the height of the wall. 6. 5 ft 6. 5 StartRoot 2 EndRoot ft 13 ft 1

navik [9.2K]

35 es mucho así que será 27 i think is 18

4 0

2 years ago

Help! How would I solve this trig identity?

NeTakaya

Using simpler trigonometric identities, the given identity was proven below.

<h3>How to solve the trigonometric identity?</h3>

Remember that:

$sec(x) = \frac{1}{cos(x)} \\\\tan(x) = \frac{sin(x)}{cos(x)}$

Then the identity can be rewritten as:

$sec^4(x) - sen^2(x) = tan^4(x) + tan^2(x)\\\\\frac{1}{cos^4(x)} - \frac{1}{cos^2(x)} = \frac{sin^4(x)}{cos^4(x)} + \frac{sin^2(x)}{cos^2(x)} \\\\$

Now we can multiply both sides by cos⁴(x) to get:

$\frac{1}{cos^4(x)} - \frac{1}{cos^2(x)} = \frac{sin^4(x)}{cos^4(x)} + \frac{sin^2(x)}{cos^2(x)} \\\\\\\\cos^4(x)*(\frac{1}{cos^4(x)} - \frac{1}{cos^2(x)}) = cos^4(x)*( \frac{sin^4(x)}{cos^4(x)} + \frac{sin^2(x)}{cos^2(x)})\\\\1 - cos^2(x) = sin^4(x) + cos^2(x)*sin^2(x)\\\\1 - cos^2(x) = sin^2(x)*sin^2(x) + cos^2(x)*sin^2(x)$