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Blizzard [7]
3 years ago
9

A(n) ____ instruction might look like a meaningless string of 0s and 1s, but it actually represents specific operations and stor

age locations.
Computers and Technology
1 answer:
V125BC [204]3 years ago
6 0

Answer:

Machine Language

Explanation:

Machine language is a collection of binary digits or bits that the computer reads and interprets.Machine language is the lowest-level programming language (except for computers that utilise programmable microcode).  Machine language is the only language a computer is capable of understanding.  The exact machine language for a program or action can differ by operating system on the computer. The specific operating system will dictate how a compiler writes a program or action into machine language.

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After the following code is executed what will be displayed on the screen? bool correntEmployee = true; double empSalary = 45000
AlexFokin [52]

Answer:

"The employee pay rate is normal" is the correct answer for the above question.

Explanation:

  • The above question code is written in the c++ language, in which there is one variable of bool type whose value is true.
  • And this variable is also tested in the if-condition which gives the true and the if-body will be executed.
  • Then the internal if-condition will give the false result because the value of the empsalary is not less than 45000. It is because the above statement "empsalary=45000" will assign the value 45000 on the empsalary variable.
  • Then the else block will be executed which prints "the employee pay rate is normal".

7 0
3 years ago
Which actions did Sheila have to take to make the changes observed? Check all that apply.
Harrizon [31]

Answer:

Use

Explanation:

Out line view

6 0
3 years ago
g Assume that this program is run on a processor with data cache of size big enough that the entire array arr can fit in the cac
Dimas [21]

Answer:

A. 2

Explanation:

The food function in the C source code uses two for loop statements to fill and array of size 100 with 100 values ranging from 1 to 100 and the second to get the total sum to the values in the array. With this, two program paths are created.

7 0
2 years ago
CHALLENGE ACTIVITY |
fredd [130]

Answer:

maxSum = FindMax(numA, numB) + FindMax(numY, numZ);  

The maxSum is a double type variable which is assigned the maximum of the two variables numA numB PLUS the maximum of the two variables numY numZ using FindMax function. The FindMax() method is called twice in this statement one time to find the maximum of numA and numB and one time to find the maximum of numY numZ. When the FindMax() method is called by passing numA and numB as parameters to this method, then method finds if the value of numA is greater than that of numB or vice versa. When the FindMax() method is called by passing numY and numZ as parameters to this method, then method finds if the value of numY is greater than that of numZ or vice versa. The PLUS sign between the two method calls means that the resultant values returned by the FindMax() for both the calls are added and the result of addition is assigned to maxSum.

Explanation:

This is where the statement will fit in the program.

#include <iostream>

using namespace std;

double FindMax(double num1, double num2) {

  double maxVal = 0.0;    

  if (num1 > num2) { // if num1 is greater than num2,

     maxVal = num1;  // then num1 is the maxVal.    }

  else {          

     maxVal = num2;  // num2 is the maxVal.   }

  return maxVal; }  

int main() {

  double numA;

  double numB;

  double numY;

  double numZ;

  double maxSum = 0.0;  

maxSum = FindMax(numA, numB) + FindMax(numY, numZ);  

  cout << "maxSum is: " << maxSum << endl;   }

Lets take an example to explain this. Lets assign values to the variables.

numA = 6.0

numB = 3.0

numY = 4.0

numZ = 9.0

maxSum =0.0

maxSum = FindMax(numA, numB) + FindMax(numY, numZ);  

FindMax(numA,numB) method call checks if numA>numB or numB>numA and returns the maximum of the two. Here numA>numB because 6.0 is greater than 3.0. So the method returns numA i.e. 6.0

FindMax(numY, numZ) method call checks if numY>numZ or numZ>numY and returns the maximum of the two. Here numZ>numY because 9.0 is greater than 4.0. So the method returns numZ i.e. 9.0

FindMax(numA, numB) + FindMax(numY, numZ) this adds the two values returned by the method FindMax for each call.

FindMax returned maxVal from numA and numB values which is numA i.e. 6.0.

FindMax returned maxVal from numY and numZ values which is numZ i.e. 9.0.

Adding these two values 9.0 + 6.0 = 15

So the complete statement  FindMax(numA, numB) + FindMax(numY, numZ) gives 15.0  as a result.

This result is assigned to maxSum. Hence

maxSum = 15

To see the output on the screen you can use the print statement as:

cout<<maxSum;

This will display 15

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