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Crazy boy [7]
3 years ago
11

What value is the 9's in 39,990?

Mathematics
1 answer:
Reptile [31]3 years ago
8 0
Thousands of your talking about 9,99O but if it's only one nine it's either tens hundreds or thousand
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Put these numbers in order from least to greatest 1/8, -0.333, -1/7
Gekata [30.6K]

Answer:

-0.333, -1/7, 1/8

Step-by-step explanation:

1/8 is the greatest because it is a positive number while the other two numbers are negative.

-0.333 or -1/3 is smaller than -1/7.

7 0
1 year ago
A drama club made $3,200 from a school play. Seventy-five percent of that amount came from ticket sales. Identify the values of
NISA [10]

Answer:

75%

Step-by-step explanation:

For this case, the first thing we will do is name variables:

a: percentage from ticket sales

b: ticket sales

We have then:

a = 75%

b = (0.75) * (3200) = $ 2400

Answer:

a = 75%

b = (0.75) * (3200) = $ 2400

The amount of ticket sales is $ 2400.

8 0
1 year ago
Please help me on this TIA!!
tamaranim1 [39]
50.24 hope it helps:)
8 0
2 years ago
Jan bought 6 cookies and 4 doughnuts for 3.50. Tom bought 12 cookies and 5 doughnuts got 5.23. Write and solve a system of equat
iren2701 [21]
0.19 for one cookie and 0.59 for one doughnut

x for how much one cookie costs and y for how much one doughnut costs
6x+4y=3.5
12x+5y=5.23

solve by substitution: (elimination would work too)
4y=3.5-6x
y=0.875-1.5x
12x+5(0.875-1.5x)=5.23
12x+4.375x-7.5x=5.23
4.5x=0.855
x=0.19
now use x to solve for y:
6(0.19)+4y=3.5
1.14+4y=3.5
2.36=4y
y=0.59

Check the work: 6(0.19)+4(0.59)=3.5
4 0
3 years ago
Simplify the number into simplest radical form. Use the factor tree to help determine the factors. StartRoot 96 Endroot StartRoo
NikAS [45]

Answer:

[tex]4608\sqrt{3}[/tex]

Step-by-step explanation:

1. \sqrt{96} *\sqrt{6}* 2*\sqrt{6}*4 *\sqrt{6} *4*\sqrt{3}

2. \sqrt{2^{5} *3} \sqrt{6} *2\sqrt{6}*4\sqrt{6}*4\sqrt{3}   <em>factoring 96</em>

<em>since \sqrt{2^{5}*3 } = \sqrt{2^{5} } \sqrt{3}</em>

3. \sqrt{2^{5} } \sqrt{3}\sqrt{6} *2\sqrt{6}*4\sqrt{6}*4\sqrt{3}

<em>using exponent rule - (a^{b}) ^{c} = a^{bc}</em>

<em> \sqrt{2^{5} } = 2^{5/2}</em>

4. 2^{5/2}\sqrt{3}\sqrt{2*3} *2\sqrt{6}*4\sqrt{6}*4\sqrt{3}

<em>doing some simple simplification and 4=2^{2}  and 6=2*3</em>

5. 2^{5/2} \sqrt{3} \sqrt{2} \sqrt{3} *2\sqrt{2} \sqrt{3} *2^{2}\sqrt{2} \sqrt{3}*4\sqrt{3}

<em>collecting the roots on one side and applying exponent rule</em>

6. \sqrt{3} \sqrt{3}\sqrt{3} \sqrt{3}\sqrt{2} \sqrt{2}\sqrt{2} *2^{5/2+1+2+2} \sqrt{3}

<em>Applying exponents rule on all \sqrt{3} and \sqrt{2}</em>

<em>7. 2^{1/2+1/2+1/2} *2^{5/2+1+2+2}*3^{1/2+1/2+1/2+1/2+1/2}</em>

<em>combining all powers of 2</em>

8. 2^{1/2+1/2+1/2+5/2+1+2+2}*3^{1/2+1/2+1/2+1/2+1/2}

<em>Simplifying</em>

9. 2^{9} *3^{2}\sqrt{3}

10. 512*9\sqrt{3}

11. 4608\sqrt{3}

3 0
3 years ago
Read 2 more answers
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