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Crazy boy [7]
3 years ago
11

What value is the 9's in 39,990?

Mathematics
1 answer:
Reptile [31]3 years ago
8 0
Thousands of your talking about 9,99O but if it's only one nine it's either tens hundreds or thousand
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Ina thangle A, B, C has sidos AB= (2m, BC=12, and
hoa [83]
(2m,BC=12) answer acidification j jfjfnf fificj 128 djdnxnx
3 0
3 years ago
75 points. Will give certified if work is shown and the answer is correct.
Svetach [21]
Volume of the first dwarf planet (r₁ = 832 mi):

V_1=\dfrac{4}{3}\cdot\pi\cdot r_1^3=\dfrac{4}{3}\cdot\pi\cdot 832^3=\dfrac{2303721472}{3}\pi\approx7.679\cdot10^8\pi\,\text{mi}^3

Volume of the second dwarf planet (r₂ = 829 mi):

V_2=\dfrac{4}{3}\cdot\pi\cdot r_2^3=\dfrac{4}{3}\cdot\pi\cdot 829^3=\dfrac{2278891156}{3}\pi\approx7.5963\cdot10^8\pi\,\text{mi}^3

So difference between the volumes is:

V_1-V_2\approx7.679\cdot10^8\pi-7.5963\cdot10^8\pi=0.0827\cdot10^8\pi=\boxed{8270000\pi\,\text{mi}^3}

or if we want exact value (we use (a³-b³) = (a-b)(a²+ab+b²) ):

V_1-V_2=\dfrac{4}{3}\cdot\pi\cdot r_1^3-\dfrac{4}{3}\cdot\pi\cdot r_2^3=\dfrac{4}{3}\pi(r_1^3-r_2^3)=\dfrac{4}{3}\pi(832^3-829^3)=\\\\\\=\dfrac{4}{3}\pi(832-829)(832^2+832\cdot829+829^2)=\\\\\\=\dfrac{4}{3}\pi\cdot3(692224+689728+687241)=4\pi\cdot2069193=\boxed{8276772\pi\,\text{mi}^3}
3 0
3 years ago
David estimates that he will have expenses totaling $24,870 for one year of college, He will receive$7,560 in grants. Howmuch wi
noname [10]

Since there are 2 semesters per year we have:

(1/2)(24,870 - 7,560) = $8,655

David would have to contribute $8,655 per semester.

5 0
3 years ago
Read 2 more answers
Help Please
yaroslaw [1]

Answer:

Its (10,∞)

Step-by-step explanation:

Trust me I just took the exam and got it correct

5 0
3 years ago
If carlos did some work and got 3x + 2x - 6 = 24 what mistake did he make
Makovka662 [10]

Carlos made the mistake that he did not combine like terms (3 x and 2 x) properly and did not use addition property of equality.

<u>Step-by-step explanation:</u>

Carlos did the work as 3 x + 2 x - 6 = 24

We need to find his mistake that he made in above given.

Here, he did not add the like terms (3 x and 2 x)

             3 x + 2 x = 5 x

Therefore, his work should be

             5 x  - 6 = 24

Also, he did not use addition property of equality. It means the equation remains same even though the same number gets added on both sides. It would be

                          5 x  - 6 = 24

                                 + 6 = + 6

                          -----------------------

                           5 x = 30

Dividing 30 by 5, we get answer as '6'. Hence,

                            x=\frac{30}{5} = 6

So, stated the above two are the mistakes found in carlos work.

4 0
3 years ago
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