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3 years ago

What is the value of x

Mathematics

1 answer:

borishaifa [10]3 years ago

5 0

$x^2=4^2+4^2\\
x^2=2\cdot16\\
x^2=32\\
x=\sqrt{32}=4\sqrt2$

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2 years ago

Susan deposits $1,200 in an account that earns 8% simple interest annually.

spayn [35]

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3 years ago

a box contains 16 cherry fruit chews, 15 peach fruit chews, and 12 plum fruit chews. Which two flavors are in the ratio 5 to 4

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2 years ago

Read 2 more answers

How to solve using substitution

DiKsa [7]

X+5 = x^2 - x + 2
0 = x^2 -2x - 3
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x = -1,3

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So we have two ordered pairs, (-1,4) and (3,8).

Hope that helped!

can you mark my answer as brainliest btw?

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2 years ago

Mark the statement either true (in all cases) or false (for at least one example). If false, construct a specific example to sho

LUCKY_DIMON [66]

Answer with Step-by-step explanation:

We are given that $v_1,v_2,..,v_4$ are in $R^4$ and $v_1,v_2,v_3$ is linearly dependent then {v_1,v_2,v_3,v_4}[/tex] is also linearly dependent.

We have to find that given statement is true or false.

Dependent vectors:Dependent vectors are those vectors in which atleast one vector is a linear combination of other given vectors.

Or If we have vectors $x_1,x_2,....x_n$

Then their linear combination

$a_1x_1+a_2x_2+.....+a_nx_n=0$

There exist at least one scalar which is not zero.

If $v_1,v_2,v_3$ are dependent vectors then

$a_1v_1+a_2v_2+a_3v_3=0$ for scalars $a_1,a_2,a_3$

Then , by definition of dependent vectors

There exist a vector which is not equal to zero

If vector $v_3$ is a linear combination of $v_1\;and \;v_2$ , So at least one of vectors in the set is a linear combination of others and the set is linearly dependent.

Hence, by definition of dependent vectors

{ $v_1,v_2,v_3,v_4$ } is linearly dependent.

Option B is true.

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3 years ago