Answer:
The minimum score required for recruitment is 668.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
Top 4%
A university plans to recruit students whose scores are in the top 4%. What is the minimum score required for recruitment?
Value of X when Z has a pvalue of 1-0.04 = 0.96. So it is X when Z = 1.75.
Rounded to the nearest whole number, 668
The minimum score required for recruitment is 668.
Step-by-step explanation:
<h3>(a) (iv) 3/14</h3>
<h3>(b) (iii) 11/14</h3>
<h3>(c) (i) 5/7</h3>
<h3>(d) (iv) 1/2</h3>
<h3>(e) (iv)The bead drawn is yellow .</h3>
When the ball hits the ground, the height is 0.
0 = 100 - 16t²
0 = (10 - 4t)(10 + 4t)
0 = 10 - 4t or 0 = 10 + 4t
4t = 10 or -4t = 10
t = 
or t = 
Time cannot be negative (unless you have a time machine) so disregard
Answer: t = 
= 2.5 seconds
We would have the following sample space:
(1, 1), (1, 2), (1, 3), (1, 4)
(2, 1), (2, 2), (2, 3), (2, 4)
(3, 1), (3, 2), (3, 3), (3, 4)
(4, 1), (4, 2), (4, 3), (4, 4)
Those give us these sums:
2, 3, 4, 5
3, 4, 5, 6
4, 5, 6, 7
5, 6, 7, 8
P(sum of 2) = 1/16 =0.0625
P(sum of 3) = 2/16 = 0.125
P(sum of 4) = 3/16 = 0.1875
P(sum of 5) = 4/16 = 0.25
P(sum of 6) = 3/16 = 0.1875
P(sum of 7) = 2/16 = 0.125
P(sum of 8) = 1/16 = 0.0625
Factor the polynomial:
4u² – 20u + 25
Rewrite – 20u as – 10u – 10u, and then factor it by grouping:
= 4u² – 10u – 10u + 25
= 2u * (2u – 5) – 5 * (2u – 5)
= (2u – 5) * (2u – 5)
= (2u – 5)² <––– this is the answer.
I hope this helps. =)
