Question

The time a basketball player spends in the air when shooting a basket is called the​ "hang time." the vertical leap l measured in feet is related to the hang time t measured in seconds by the equation equals=4t squared 4t2. suppose that a basketball player has a vertical leap of 44 feet 1111 inches. find the hang time for this leap.

Answer 1

Answer: 1.1 seconds

Step-by-step explanation:

leap = 4t²  ; leap = 4 ft 11 inches, find t

$4\frac{11}{12} = 4t^2$

$\frac{59}{12} = 4t^2$

$\frac{59}{48} = t^2$

$\sqrt{\frac{59}{12}} = \sqrt{t^2}$

$\sqrt{1.23} = t$

1.1 = t