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Radda [10]
3 years ago
7

You invested $11,000 in two accounts paying 3% and 7% annual interest, respectively. If the total interest earned for the year w

as $730, how much was invested at each rate? The amount invested at 3% is $​
Mathematics
2 answers:
Trava [24]3 years ago
6 0

Answer:

I invested $ 10,000 at 7% per year, and $ 1,000 at 3% per year.

Step-by-step explanation:

Given that I invested $ 11,000 in two accounts paying 3% and 7% annual interest, respectively, if the total interest earned for the year was $ 730, to determine how much was invested at each rate, the following calculation must be performed:

5,000 x 0.07 + 6,000 x 0.03 = 530

8,000 x 0.07 + 3,000 x 0.03 = 650

10,000 x 0.07 + 1,000 x 0.03 = 730

Therefore, I invested $ 10,000 at 7% per year, and $ 1,000 at 3% per year.

Naddik [55]3 years ago
3 0

Answer:

A 3% = 1000 and B 7% = 10000

Step-by-step explanation:

A + B = 11000

A * 0.03 + B * 0.07 = $730

A = 11000 - B

(11000 - B)*0.03 + B*0.07 = 730

330 - 0.03B + 0.07B = 730

330 + 0.04B = 730

0.04B = 400

B = 10000

A = 11000 - B = 11000 - 10000

A = 1000

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oee [108]

Answer:

Three consecutive numbers are 27,28,29

Step-by-step explanation:

Given :  The sum of three consecutive integers is 84.

To find : What are the integers?

Solution : Let three consecutive numbers x, x+1, x+2

So, according to given situation 'sum of three consecutive integers is 84'.

x+x+1+x+2=84

\Rightarrow 3x+3=84

\Rightarrow 3x=84-3=81

\Rightarrow x=\frac{81}{3}

\Rightarrow x=27

So,x=27

x+1= 27+1=28

x+2=27+2=29

Therefore, three consecutive numbers are 27,28,29

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