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Radda [10]
2 years ago
7

You invested $11,000 in two accounts paying 3% and 7% annual interest, respectively. If the total interest earned for the year w

as $730, how much was invested at each rate? The amount invested at 3% is $​
Mathematics
2 answers:
Trava [24]2 years ago
6 0

Answer:

I invested $ 10,000 at 7% per year, and $ 1,000 at 3% per year.

Step-by-step explanation:

Given that I invested $ 11,000 in two accounts paying 3% and 7% annual interest, respectively, if the total interest earned for the year was $ 730, to determine how much was invested at each rate, the following calculation must be performed:

5,000 x 0.07 + 6,000 x 0.03 = 530

8,000 x 0.07 + 3,000 x 0.03 = 650

10,000 x 0.07 + 1,000 x 0.03 = 730

Therefore, I invested $ 10,000 at 7% per year, and $ 1,000 at 3% per year.

Naddik [55]2 years ago
3 0

Answer:

A 3% = 1000 and B 7% = 10000

Step-by-step explanation:

A + B = 11000

A * 0.03 + B * 0.07 = $730

A = 11000 - B

(11000 - B)*0.03 + B*0.07 = 730

330 - 0.03B + 0.07B = 730

330 + 0.04B = 730

0.04B = 400

B = 10000

A = 11000 - B = 11000 - 10000

A = 1000

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Answer:

d) 330

Step-by-step explanation:

The number of ways can a dance instructor send 4 of her 11 students to summer dance program is  C(11 , 4)

That is 11_{C_{4} } ways

by using formula n_{C_{r} } = \frac{n!}{(n-r)!r!}

now simplification

11_{C_{4} } = \frac{11!}{(11-4)!4!}

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after cancelling 7! and on simplification

   = \frac{11X10X9X8}{4X3X2X1}

after cancellation we get 330 ways

The number of ways can a dance instructor send 4 of her 11 students to summer dance program is 330

   

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Step-by-step explanation:

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