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Radda [10]
3 years ago
7

You invested $11,000 in two accounts paying 3% and 7% annual interest, respectively. If the total interest earned for the year w

as $730, how much was invested at each rate? The amount invested at 3% is $​
Mathematics
2 answers:
Trava [24]3 years ago
6 0

Answer:

I invested $ 10,000 at 7% per year, and $ 1,000 at 3% per year.

Step-by-step explanation:

Given that I invested $ 11,000 in two accounts paying 3% and 7% annual interest, respectively, if the total interest earned for the year was $ 730, to determine how much was invested at each rate, the following calculation must be performed:

5,000 x 0.07 + 6,000 x 0.03 = 530

8,000 x 0.07 + 3,000 x 0.03 = 650

10,000 x 0.07 + 1,000 x 0.03 = 730

Therefore, I invested $ 10,000 at 7% per year, and $ 1,000 at 3% per year.

Naddik [55]3 years ago
3 0

Answer:

A 3% = 1000 and B 7% = 10000

Step-by-step explanation:

A + B = 11000

A * 0.03 + B * 0.07 = $730

A = 11000 - B

(11000 - B)*0.03 + B*0.07 = 730

330 - 0.03B + 0.07B = 730

330 + 0.04B = 730

0.04B = 400

B = 10000

A = 11000 - B = 11000 - 10000

A = 1000

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OverLord2011 [107]

Answer:

The correct answer is option B.

Step-by-step explanation:

When one of them loses their job, their monthly income is reduced by $3,200. If they felt the need to file for bankruptcy, then the following statements is true?-

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4 0
3 years ago
Read 2 more answers
2logx=3-2log(x+3) solve for x​
AVprozaik [17]

Answer:

\large\boxed{x=\dfrac{-3+\sqrt{40+10\sqrt{10}}}{2}}

Step-by-step explanation:

2\log x=3-2\log(x+3)\\\\Domain:\ x>0\ \wedge\ x+3>0\to x>-3\\\\D:x>0\\============================\\2\log x=3-2\log(x+3)\qquad\text{add}\ 2\log(x+3)\ \text{to both sides}\\\\2\log x+2\log(x+3)=3\qquad\text{divide both sides by 2}\\\\\log x+\log(x+3)=\dfrac{3}{2}\qquad\text{use}\ \log_ab+\log_ac=\log_a(bc)\\\\\log\bigg(x(x+3)\bigg)=\dfrac{3}{2}\qquad\text{use the de}\text{finition of a logarithm}\\\\x(x+3)=10^\frac{3}{2}\qquad\text{use the distributive property}

x^2+3x=10^{1\frac{1}{2}}\\\\x^2+3x=10^{1+\frac{1}{2}}\qquad\text{use}\ a^n\cdot a^m=a^{n+m}\\\\x^2+3x=10\cdot10^\frac{1}{2}\qquad\text{use}\ \sqrt[n]{a}=a^\frac{1}{n}\\\\x^2+3x=10\sqrt{10}\qquad\text{subtract}\ 10\sqrt{10}\ \text{from both sides}\\\\x^2+3x-10\sqrt{10}=0\\\\\text{Use the quadratic formula}\\\\ax^2+bx+c=0\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\a=1,\ b=3,\ c=-10\sqrt{10}\\\\b^2-4ac=3^2-4(1)(-10\sqrt{10})=9+40\sqrt{10}\\\\x=\dfrac{-3\pm\sqrt{40+10\sqrt{10}}}{2(1)}=\dfrac{-3\pm\sqrt{40+10\sqrt{10}}}{2}\\\\x=\dfrac{-3-\sqrt{10+10\sqrt{10}}}{2}\notin D

6 0
3 years ago
A prefix kilo in the metric system means ___ units. A. 100 B 10 C.1,000 D.1,000,000
siniylev [52]
Kilo = 1,000
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8 0
3 years ago
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Need help due in 10 mins
Marina CMI [18]

Answer:

A) The amount of money deposited monthly

Step-by-step explanation:

y = 35x (slope) (amount deposited each month)+ 250 (y-intercept) (starting amount)

4 0
2 years ago
A cylinder and a cone have the same volume. The cylinder has radius x and height y. The cone has radius 1/3x. Find the height of
Temka [501]

Great question! I had this question in Geometry on Edmentum.

Answer: Height of cone = 3y

Step-by-step explanation:

We know that the cylinder and the cone have the same volume. The cylinder has radius x and height y. We will make use of the formulas:

Volume of cylinder = πr²h

Volume of cone = 1/3πr²h

Since the cone has radius 1/3x, we will have to make its height 3 times of y (the height of the cylinder) to make both the cylinder and the cone have the same volume.

So, the height of the cone is equal to 3y.

Hope this helps, and have a wonderful day! :D

Please mark me brainliest! I don't have trouble getting points, but I do when it comes to brainliest.

7 0
3 years ago
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