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Rudiy27
3 years ago
11

At a doctor's appointment, a baby weighed 10 pounds. How many ounces did the baby weigh?

Mathematics
1 answer:
Sergio [31]3 years ago
4 0

Answer:

The baby would be 160 ounces.

Step-by-step explanation:

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What is the answer for 2x+y=2
beks73 [17]

Answer:

X=1 - y/2

Step-by-step explanation:

2x = 2 - y

divide both sides by 2

x = 1 - y/2

4 0
3 years ago
Use the normal distribution to find a confidence interval for a proportion p given the relevant sample results. Give the best po
Brrunno [24]

Answer: (0.63, 7.07)

Step-by-step explanation:

The confidence interval for population proportion is given by :-

\hat{p}\pm z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

Given :\hat{p} =0.7 ;  n=110

Significance level : 1-0.90=0.1

Critical value :  z_{\alpha/2}=1.645

Now, a 90% confidence interval for population proportion will be :-

0.7\pm (1.645)\sqrt{\dfrac{0.7(1-0.7)}{110}}\\\\\approx0.7\pm0.07\\\\=(0.7-0.07,0.7+0.07)=(0.63,\ 7.07)

Hence, a 90% confidence interval for population proportion = (0.63, 7.07)

5 0
3 years ago
Real World Scenario:
iragen [17]

The distance of a train from the city depends on the speed, the time of

travel, and direction of motion of the train.

Correct responses:

  • Distance Train A is from the city: <u>750 - 75·t</u>
  • Distance Train B is from the city: 50·t
  • After <u>six</u> hours, the two trains are the same distance from the city
  • At that time both trains will be <u>300</u> miles away

1) From the time of departure of Train B to just before 6 hours after Train B's departure; 0 ≤ t < 6 hours

2) At time period, t > 6 hours

3) 250 miles

<h3>Method used to find the above response</h3>

Given:

The distance of train A from the city = 750 miles

Speed of train A = 75 mph

Time at which Train B leaves the city = When Train A is 750 miles from the city

Speed of Train B = 50 mph

Solution:

The equations are;

  • Distance of Train A from the city is; <u>x₁ = 750 - 75·t</u>
  • Distance of Train B from the city is <u>x₂ = 50·t</u>

When the train are the same distance from the city, we have;

750 - 75·t = 50·t

750 = 50·t + 75·t = 125·t

Therefore;

  • t = \mathbf{\dfrac{750}{125}} = 6

The time it takes the two trains to be the same distance from the city is 6 hours.

Which gives;

  • After <u>6</u> hours, the two trains are the same distance from the city.

The distance the trains will be after 6 hours is therefore;

750 - 75 × 6 = 300

The distance of the trains from the city after 6 hours = 300 miles

Therefore, we have;

  • At that time both trains will be <u>300</u> miles away

1) The time period Train A is further from the city is before the first 6 hours elapse; <u>0 hours ≤ t < 6 hours</u>

2) The Train B is further from the city after 6 hours of its departure from the city; <u>t > 6 hours</u>

3) The distance of Train A from the city after 4 hours is given as follows;

x₁ = 750 - 75 × 4 = 450

x₁ = 450 miles

The distance of Train B from the city after 4 hours is; x₂ = 50 × 4 = 200

x₂ = 200 miles

Therefore;

  • The distance between the trains after 4 hours = 450 miles - 200 miles = <u>250 miles</u>

Learn more about distance and time relationship equation here:

brainly.com/question/10804931

3 0
2 years ago
Which value of y makes the inequality 3y^2 + 2(y - 5) &gt;8 true?
AveGali [126]

Answer:

-3

Step-by-step explanation:

7 0
3 years ago
What is the multiplicity of the root 2 in the equation x^3-8x^2+20x-16=0?
mote1985 [20]
Factoring the cubic you get: <span>(x - 2)^2 (x-4) , so we know the multiplicity is the amount of times a root shows in an equation because the equation (x-2) has a exponent of 2 that means the root 2 has a multiplicity of 2.</span>
Answer: 2
8 0
3 years ago
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