The difference of twice a number and five is three. Find the number.

^ which equation represents the relationship shown in the table ??

Butoxors [25]

Answer:

y=2x+5

Step-by-step explanation:

7 0

3 years ago

Help me u get brainliest plus more points :D

vredina [299]

Answer:

6 is 56.25

7 is 97.50

Step-by-step explanation:

7 0

3 years ago

Because of a problem in the program, the timer in a video player did not begin counting until the video had been playing for sev

stich3 [128]

Answer:

105

Step-by-step explanation:

t = 0

frame = 190

so it means, the video has 190 before the timer start counting

speed 25 fps

-------

t = -3 2/5 s = -17/5 s

frame = ?

with the rate of 25 fps

it gain 25 x -17/5 = 85 frame.

so the video at that time has already played

190-85 = 105 frame

5 0

3 years ago

I’m stuck, HELP 3(6) + 4(2)^3 - 5

Slav-nsk [51]

Answer:

45

Step-by-step explanation:

Lets split the problem then add/subtract at the end

3 x 6 = 18

Due to Order of operations we do 2^3 first then multipy by 4

so 2^3 = 8 Then we do 8 x 4 = 32

Now we add/subtract

18 + 32 - 5 = 45

45 is the answer

4 0

3 years ago

Read 2 more answers

Find the quotient (line over 42 is repeating)

strojnjashka [21]

The correct answer is: [C]: " $\frac{21}{11}$ " .
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Explanation:
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Let us begin by converting the:
"0.42 (with the "repeating bar on the digits, "42") " ;

into a fraction, as follows:
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Let x = 0.42424242424242424242424242424242....

100x = 42.42424242424242424242424242424242....
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100x = 42.42424242424242424242424242424242....
– x = 0.42424242424242424242424242424242...
______________________________________________________
99x = 42.000000000000000000000000000000.... ;

→ 99x = 42 ;

Divide each side of the equation by " 99 " ;
to isolate "x" on one side of the equation; & to solve for "x" ;
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→ 99x / 99 = 42/99 = (42 ÷ 3) / (99 ÷ 3) = 14/ 33;

→ x = " $\frac{14}{33}$ " .

So; "0.42 (with a repeating bar over the digits, "42" ;

is equal to: " $\frac{14}{33}$ "
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So, rewrite the question/problem being asked:
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"Find the quotient:
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$\frac{14}{33}$ ÷ $\frac{2}{9}$ ;

= $\frac{14}{33}$ * $\frac{9}{2}$ ;

Note: The "14" cancels to a "7" ; and the "2" cancels to a "1" ;
→ {since: " 14 ÷ 2 = 7 " ; and since: " 2 ÷ 2 = 1 "} ;

Note : The "33" cancels to an "11" ; and the "9" cancels to a "3" ;
 → {since: " 33 ÷ 3 = 11 " ; and since: " 9 ÷ 3 = 3 "} ;

And we can rewrite the problem as:
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" $\frac{7}{11}$ * $\frac{3}{1}$ " ;

= $\frac{(7*3)}{(11*1}$ = $\frac{21}{11}$ ;

→ which is: Answer choice: [C]: " $\frac{21}{11}$ " .
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3 0

4 years ago