The solution to the quadratic equation by using a numeric approach
are x = 6.3 and x = -31.3
Given the quadratic function expressed as;
0.02x²+ 0.5x - 4 = 0
Multiply through by 100 to have;
2x² + 50x - 400 = 0
Using the general formula to solve:
x = -50±√2500-4(2)(-400)/2(2)
x = -50±√2500+3200/4
x = -50±75.49/4
x = -31.3 or 6.3
Hence the solution to the quadratic equation by using a numeric approach
are x = 6.3 and x = -31.3
Learn more on quadratic function here: brainly.com/question/25841119
AX = b or ![\left[\begin{array}{cc}1&1\\0.1&0.05\end{array}\right] \left[\begin{array}{c}x\\y\end{array}\right] = \left[\begin{array}{c}15\\1.10\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%261%5C%5C0.1%260.05%5Cend%7Barray%7D%5Cright%5D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dx%5C%5Cy%5Cend%7Barray%7D%5Cright%5D%20%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D15%5C%5C1.10%5Cend%7Barray%7D%5Cright%5D)
<h3>
The above matrix can be used to determine the number of dimes x and nickels y.</h3>
Step-by-step explanation:
Here, total number of coins = 15
Let us assume the number of dimes = x
Also, let us assume the number of nickels = y
So, x + y = 15 .... (1)
Again, 1 dime = $0.1
So, x dimes = x ($0.1) = $ (0.1 x)
1 nickel = $0.05
So, y nickels = y ($0.05) = $ (0.05 y)
Also, total value of coins = $1.10
⇒ 0.1 x + 0.05 y = 1.10 .... (2)
So, from (1) and (2) the matrix can be written as:
AX = b or
The above matrix can be used to determine the number of dimes x and nickels y.
It is asking you to substitute or plug in the values.
Example:
Evaluate 3r(s+3) if r = -3 and s = 5
See that r? It means that you put in -3 in place of the r, and you put 5 in place of the s so it looks like this:
3*-3(5+3)
Now solve that using order of operations and you should get
-9*(5+3) (don't forget that your'e distributing here FIRST then add)
-45+-27
-72
That's how you solve an expression like that. This is only an EXAMPLE. Hope it helped.
