Answer:
The factors of given expression are 10+10√2 and 10-10√2.
Step-by-step explanation:
We have given a quadratic expression.
s²-20s-100
We have to find factors of given expression.
We use quadratic formula to find factors.
x = (-b±√b²-4ac) / 2a
From given expression, a = 1 , b = -20 and c = -100
Putting values in above formula, we have
x = (-(-20)±√(-20)²-4(1)(-100) ) / 2(1)
x = (20±√400+400 ) / 2
x = (20±√800) / 2
x = (20± √400×2) / 2
x = (20±20√2) / 2
x = 10±10√2
Hence, the factors of given expression are 10+10√2 and 10-10√2.
Answer:
Plzzz
Step-by-step explanation:
Zoom innnn plzz
Answer:
circumference - diameter
circumference - 2 times radius
area - radius squared
Step-by-step explanation:
we know that
<u><em>The circumference of a circle is equal to</em></u>
or 
where
D is the diameter and r is the radius
therefore
or 
The number pi is the ratio circumference - diameter or is the ratio circumference - 2 times radius
<u><em>The area of the circle is equal to</em></u>

therefore

The number pi is the ratio Area - radius squared
-10y And = -2 so it would be 12x + (-10y) = -2
OA and OC are radii of the circle. Hence, OA = OC. So if AO = 40, then OC = 40.
Length of BO = 40 + 45
= 85
Using the Pythagoras theorem, you can find out the length of AB since tangents to the circle always have an angle of 90 with the circle.
AB^2 = BO^2 + AO^2
AB^2 = 85^2 + 40^2
AB^2 = 7225 + 1600
AB^2 = 8825
AB = root of 8225
AB = 90.69 to 2 decimal places.
Hopefully this helped :)