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2 years ago

8 1/3% as a fraction

Mathematics

1 answer:

ELEN [110]2 years ago

4 0

Answer:

Ok wait 8 and 1 third as a fraction cause it already is OR 81 divided by 3 as a fraction? If its 81 then the answer would be 27/1

Step-by-step explanation:

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HELP PLEASE!! Will mark brainliest to correct answer

swat32

Answer:

Step-by-step explanation:

KL- because triangle is a isosceles

(base angles are congruent)

8 0

2 years ago

a team of 15 workers cad do a job in 7 hours. How long would this work take if the team has 35 people?

tankabanditka [31]

Answer:

3 hours

Step-by-step explanation:

15 workers * 7 hours = 105 worker hours

105 worker hours / 35 workers = 3 hours

8 0

1 year ago

For the pair of similar triangles, find the value of x.

Murljashka [212]

Find the scale between sides xz and gh

18/4 = 4.5

Multiply the length of fh by the scale to find x

6 x 4.5 = 27

x = 27

7 0

2 years ago

Find the area of the part of the plane 3x 2y z = 6 that lies in the first octant.

gavmur [86]

The area of the part of the plane 3x 2y z = 6 that lies in the first octant is mathematically given as

A=3 √(4) units ^2

<h3>What is the area of the part of the plane 3x 2y z = 6 that lies in the first octant.?</h3>

Generally, the equation for is mathematically given as

The Figure is the x-y plane triangle formed by the shading. The formula for the surface area of a z=f(x, y) surface is as follows:

$A=\iint_{R_{x y}} \sqrt{f_{x}^{2}+f_{y}^{2}+1} d x d y(1)$

The partial derivatives of a function are f x and f y.

$\begin{aligned}&Z=f(x)=6-3 x-2 y \\&=\frac{\partial f(x)}{\partial x}=-3 \\&=\frac{\partial f(y)}{\partial y}=-2\end{aligned}$

When these numbers are plugged into equation (1) and the integrals are given bounds, we get:

$&=\int_{0}^{2} \int_{0}^{3-\frac{3}{2} x} \sqrt{(-3)^{2}+(-2)^2+1dxdy} \\\\&=\int_{0}^{2} \int_{0}^{3-\frac{3}{2} x} \sqrt{14} d x d y \\\\&=\sqrt{14} \int_{0}^{2}[y]_{0}^{3-\frac{3}{2} x} d x d y \\\\&=\sqrt{14} \int_{0}^{2}\left[3-\frac{3}{2} x\right] d x \\\\$

$&=\sqrt{14}\left[3 x-\frac{3}{2} \cdot \frac{1}{2} \cdot x^{2}\right]_{0}^{2} \\\\&=\sqrt{14}\left[3-\frac{3}{2} \cdot \frac{1}{2} \cdot x^{2}\right]_{0}^{2} \\\\&=\sqrt{14}\left[3.2-\frac{3}{2} \cdot \frac{1}{2} \cdot 3^{2}\right] \\\\&=3 \sqrt{14} \text { units }{ }^{2}$

In conclusion, the area is

A=3 √4 units ^2