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eimsori [14]
3 years ago
15

Can someone please help solve this equation? log, 4r = 4 12

Mathematics
1 answer:
rjkz [21]3 years ago
6 0

Step-by-step explanation:

I think the answer might be 2

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Ayudaaaaaaaaaaaaaaaaaa aaa aaa aaa Doy corona
zvonat [6]

Answer:

The IQR describes the middle 50% of values when ordered from lowest to highest. To find the interquartile range (IQR), ​first find the median (middle value) of the lower and upper half of the data. These values are quartile 1 (Q1) and quartile 3 (Q3). The IQR is the difference between Q3 and Q1.

Step-by-step explanation:

6 0
3 years ago
Does anyone know this?
barxatty [35]

Answer:

\Huge \boxed{-2}

Step-by-step explanation:

f(x)=-2x^2-2x+10

For f(2), the input of the function is 2.

Let x = 2.

f(2)=-2(2)^2-2(2)+10

Evaluate.

f(2)=-2(4)-2(2)+10

f(2)=-8-4+10

f(2)=-2

8 0
3 years ago
Read 2 more answers
Consider the equation q= 4 +0.8p.<br> What value of q would make the equation true when p<br> is 7?
NARA [144]

Answer:

9.6

Step-by-step explanation:

q=4+0.8(7)

6 0
3 years ago
What is the area of the shaded region? Use 3.14 for π and round your answer to the nearest tenth.
Musya8 [376]
3.14(10²) - 3.14(6²)
3.14(10² - 6²)
3.14(100 - 36)
3.14(64)
200.96
201

3 0
3 years ago
Read 2 more answers
What is the inverse of f(x)=2^x
GuDViN [60]

Answer:

<h2>{f}^{ - 1} (x) =  \frac{ln(x)}{ln(2)}</h2>

Step-by-step explanation:

f(x)=2^x

y =  {2}^{x}

x =  {2}^{y}

{2}^{y}  = x

ln( {2}^{y} )=ln(x)

yln(2)=ln(x)

<h3>\frac{yln(2)}{ln(2)}  =  \frac{ln(x)}{ln(2)}</h3><h3>y =  \frac{ln(x)}{ln(2)}</h3><h3>{f}^{ - 1} (x) =  \frac{ln(x)}{ln(2)}</h3><h3>Hope it is helpful...</h3>
3 0
3 years ago
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