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3 years ago

How does the graph change from point G to point K?

Mathematics

2 answers:

ss7ja [257]3 years ago

6 0

Look at ur line starting at point G....it goes up a little, then goes down...therefore, it increases, then decreases

Eduardwww [97]3 years ago

3 0

Answer:

Option: d is correct.

( Hence the change in the graph from point G to point K is:

d.The graph increases, then decreases)

Step-by-step explanation:

Clearly after looking at the graph we could observe that graph first increases from point G to point (0,3) and then it decreases from point (0,3) to point K.

Hence, the behavior of the graph or the change of the graph from Point G to Point K is that:

The graph increases, then decreases.

Hence, option d is correct.

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Ruth has a beaker containing a solution of 800 mL of acid and 200 mL of water. She thinks the solution is a little strong, so sh

Alexeev081 [22]

Answer:

Step-by-step explanation:

Ok so the beaker is 200 water:800 acid

So she drains 100 from the acid and 100 from the water which equals

100:700

Then she adds 200 water:

300:700

there is 300 mL water in da beaker now

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5 0

3 years ago

Convert the improper fraction to a mixed number.<br> negative StartFraction 28 Over 3 EndFraction

Burka [1]

How many times does 3 go into 28? let's see 28÷3 is 9.333 so...9 whole times, thus 9 * 3 is 27 so

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8 0

4 years ago

How do I solve this? <br>8(7+23)=8(7)+8()

rodikova [14]

USE PEMDAS
8(7+23)=8(7)+8(23)
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6 0

3 years ago

A College Alcohol Study has interviewed random samples of students at four-year colleges. In the most recent study, 494 of 1000

Vinil7 [7]

Answer:

The 95% confidence interval for the difference between the proportion of women who drink alcohol and the proportion of men who drink alcohol is (-0.102, -0.014) or (-10.2%, -1.4%).

Step-by-step explanation:

We want to calculate the bounds of a 95% confidence interval of the difference between proportions.

For a 95% CI, the critical value for z is z=1.96.

The sample 1 (women), of size n1=1000 has a proportion of p1=0.494.

$p_1=X_1/n_1=494/1000=0.494$

The sample 2 (men), of size n2=1000 has a proportion of p2=0.552.

$p_2=X_2/n_2=552/1000=0.552$

The difference between proportions is (p1-p2)=-0.058.

$p_d=p_1-p_2=0.494-0.552=-0.058$

The pooled proportion, needed to calculate the standard error, is:

$p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{494+552}{1000+1000}=\dfrac{1046}{2000}=0.523$

The estimated standard error of the difference between means is computed using the formula:

$s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.523*0.477}{1000}+\dfrac{0.523*0.477}{1000}}\\\\\\s_{p1-p2}=\sqrt{0.000249+0.000249}=\sqrt{0.000499}=0.022$