Answer:
The value of c = -0.5∈ (-1,0)
Step-by-step explanation:
<u>Step(i)</u>:-
Given function f(x) = 4x² +4x -3 on the interval [-1 ,0]
<u> Mean Value theorem</u>
Let 'f' be continuous on [a ,b] and differentiable on (a ,b). The there exists a Point 'c' in (a ,b) such that

<u>Step(ii):</u>-
Given f(x) = 4x² +4x -3 …(i)
Differentiating equation (i) with respective to 'x'
f¹(x) = 4(2x) +4(1) = 8x+4
<u>Step(iii)</u>:-
By using mean value theorem


8c+4 = -3-(-3)
8c+4 = 0
8c = -4

c ∈ (-1,0)
<u>Conclusion</u>:-
The value of c = -0.5∈ (-1,0)
<u></u>
(2, 8) because 8 is not negative
hope it helps,
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Answer:
(x, y, z) = (1, 2, 3)
Step-by-step explanation:
The equations that result from reduction to row-echelon form are ...
x = 0.4 +0.2t
y = 5.6 -1.2t
z = t
Then t must have a value 5n+3 for 0 ≤ n < 1. That is, t=3.
x = 0.4 +0.2(3) = 1
y = 5.6 -1.2(3) = 2
z = 3
The integers that satisfy are (x, y, z) = (1, 2, 3).